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Bunuel

FRESH GMAT CLUB TESTS QUESTION



If n is a positive integer, what is the remainder when n is divided by 5?

(1) The remainder when n^2 is divided by 5 is 4
(2) The remainder when n + 10 is divided by 5 is 3

#1
n=2 or 3
so n^2 = 4 remainder possible insufficient
#2
n=3,13,23,33,8,18 we get remainder 3 dividing by 5 value of n+10..

from 1 & 2
n=3 only possible
IMO C
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The question is what is the reminder when n is divided by 5.

From statement B it is clear that regardless if the figure is 3, 13, 18 or 8 (as other users proposed) the reminder will always be N/3 = X + 3

So statement B is enough to answer the question
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In statement 2 if n+10 is divided by 5 remainder is 3. So as 10 is a multiple of 5 hence n when divided by 5 remainder should always be 3. and statement b should be sufficient to answer the question. Why the OA is 3. Can you please explain Bunuel

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I am still unclear why B is sufficient.

if n=3 -> 3/5 has a remainder of 5. if n=13 -> 13/5 has a reminder of 3.
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I am still unclear why B is sufficient.

if n=3 -> 3/5 has a remainder of 5. if n=13 -> 13/5 has a reminder of 3.

3 divided by 5 gives the remainder of 3, not 5.

When the divisor (5 in your case) is more than dividend (3 in your case) then the reminder equals to the dividend.

For example:
3 divided by 24 yields a reminder of 3 --> \(3=0*24+3\);
or:
5 divided by 6 yields a reminder of 5 --> \(5=0*6+5\),
or example from your post:
2 divided by 5 yields a reminder of 2 --> \(2=0*5+2\).

Hope it's clear.
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