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12=(2*2*3)n+3
24=(2*2*2*3)n+3
80=(5*2*2*2*2)n+3
90=(5*2*3*3)n+2
120=(5*2*2*2*3)n+3

for 4: all gives remainder 3 exc. D with remainder 0, D out
for 5: A and B gives remainder 0 and 2, respectively, so they out
for 6: E gives remander 3

E
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BrainLab
If n is a positive integer, which one of the following numbers must have a remainder of 3 when
divided by any of the numbers 4, 5, and 6?

(A) 12n + 3
(B) 24n + 3
(C) 80n + 3
(D) 90n + 2
(E) 120n + 3

Source: GMAT Math Bible

4*5*6=120
E
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Hello from the GMAT Club BumpBot!

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