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If n is a prime number between 0 and 100, how many positive divisors

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If n is a prime number between 0 and 100, how many positive divisors [#permalink]

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20 Apr 2016, 00:03
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If n is a prime number between 0 and 100, how many positive divisors does n^3 have?

A. 1
B. 2
C. 3
D. 4
E. 5
[Reveal] Spoiler: OA

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Joined: 10 Apr 2016
Posts: 55
Concentration: Strategy, Entrepreneurship
GMAT 1: 520 Q29 V30
GPA: 3.01
Re: If n is a prime number between 0 and 100, how many positive divisors [#permalink]

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20 Apr 2016, 01:37
I'd say the answer is 1 because every divisor is just a multiple of the original prime?
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Took the Gmat and got a 520 after studying for 3 weeks with a fulltime job. Now taking it again, but with 6 weeks of prep time and a part time job. Studying every day is key, try to do at least 5 exercises a day.

Math Expert
Joined: 02 Aug 2009
Posts: 5660
Re: If n is a prime number between 0 and 100, how many positive divisors [#permalink]

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20 Apr 2016, 01:51
2
KUDOS
Expert's post
I'd say the answer is 1 because every divisor is just a multiple of the original prime?

Hi,
we are basically looking it factors of$$n^3,$$ where n is a PRIME number..
number of factors $$= (3+1) = 4.$$.
we can also write them down.
1, n, $$n^2$$, and $$n^3$$
so ans will be 4
D
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Absolute modulus :http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html

BANGALORE/-

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Joined: 10 Apr 2016
Posts: 55
Concentration: Strategy, Entrepreneurship
GMAT 1: 520 Q29 V30
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Re: If n is a prime number between 0 and 100, how many positive divisors [#permalink]

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20 Apr 2016, 01:57
chetan2u wrote:
I'd say the answer is 1 because every divisor is just a multiple of the original prime?

Hi,
we are basically looking it factors of$$n^3,$$ where n is a PRIME number..
number of factors $$= (3+1) = 4.$$.
we can also write them down.
1, n, $$n^2$$, and $$n^3$$
so ans will be 4
D

Hi chetan. Could you explain the rule for this? Is it only for prime numbers?

Thank you!
_________________

Took the Gmat and got a 520 after studying for 3 weeks with a fulltime job. Now taking it again, but with 6 weeks of prep time and a part time job. Studying every day is key, try to do at least 5 exercises a day.

Math Expert
Joined: 02 Aug 2009
Posts: 5660
If n is a prime number between 0 and 100, how many positive divisors [#permalink]

Show Tags

20 Apr 2016, 02:03
chetan2u wrote:
I'd say the answer is 1 because every divisor is just a multiple of the original prime?

Hi,
we are basically looking it factors of$$n^3,$$ where n is a PRIME number..
number of factors $$= (3+1) = 4.$$.
we can also write them down.
1, n, $$n^2$$, and $$n^3$$
so ans will be 4
D

Hi chetan. Could you explain the rule for this? Is it only for prime numbers?

Thank you!

Hi,

when ever you are looking for the number of factors/positive divisors, get the integer in its simplest form/scientific notation ..
for example say 36..
$$36 = 2^2*3^2$$.. ans will be (2+1)(2+1) = 3*3=9..
$$120 = 2^3*3*5$$.. ans will be (3+1)(1+1)(1+1) = 4*2*2=16..

say a Q further asks you ODD factor of 120..
just drop the even 2-- (3+1)(1+1)(1+1) .. ans will be (1+1)(1+1)=2*2=4..
Even factors will be Total - ODD = 16-4=12..
May help somewhere
_________________

Absolute modulus :http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html

BANGALORE/-

Math Expert
Joined: 02 Sep 2009
Posts: 43893
Re: If n is a prime number between 0 and 100, how many positive divisors [#permalink]

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20 Apr 2016, 02:05
chetan2u wrote:
I'd say the answer is 1 because every divisor is just a multiple of the original prime?

Hi,
we are basically looking it factors of$$n^3,$$ where n is a PRIME number..
number of factors $$= (3+1) = 4.$$.
we can also write them down.
1, n, $$n^2$$, and $$n^3$$
so ans will be 4
D

Hi chetan. Could you explain the rule for this? Is it only for prime numbers?

Thank you!

Finding the Number of Factors of an Integer:

First make prime factorization of an integer $$n=a^p*b^q*c^r$$, where $$a$$, $$b$$, and $$c$$ are prime factors of $$n$$ and $$p$$, $$q$$, and $$r$$ are their powers.

The number of factors of $$n$$ will be expressed by the formula $$(p+1)(q+1)(r+1)$$. NOTE: this will include 1 and n itself.

Example: Finding the number of all factors of 450: $$450=2^1*3^2*5^2$$

Total number of factors of 450 including 1 and 450 itself is $$(1+1)*(2+1)*(2+1)=2*3*3=18$$ factors.

Check for more here: math-number-theory-88376.html
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Re: If n is a prime number between 0 and 100, how many positive divisors [#permalink]

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20 Apr 2016, 12:45
Two ways to solve this one
Pick has 2 => 8 has 4 factors hence D
next way to solve this up is using the formula => if K=P^a * Q^b * R^c where P,Q,R are primes ; then the number of divisors of K are => a+1 * b+1 * c+1

Hit that D option .
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Re: If n is a prime number between 0 and 100, how many positive divisors [#permalink]

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22 May 2017, 18:39
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Re: If n is a prime number between 0 and 100, how many positive divisors   [#permalink] 22 May 2017, 18:39
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