CAMANISHPARMAR
If n is a three-digit positive integer, what is the tens digit of n?
(1) Dividing n by 4 gives the same remainder as does dividing n by 25.
(2) Dividing n by 16 gives the same remainder as does dividing n by 25.
Given n is a three digit number, required is tens digit of n.
Statement 1:
Let \(r\) be remainder, then
\(n = 4k + r\), \(0<=r<4\)
\(n = 25q + r\), \(0<=r<25\)
Hence \(0<=r<4\), \(r = 0,1,2,3\)
LCM of \(4\) & \(25\) is \(100\), hence \(n = 100p + r\)
So r will be units digit of a multiple of 100, hence the tens digit of n will be 0.
Statement 1 is sufficient.
Statement 2:
Let \(z\) be remainder, then
\(n = 16x + z\), \(0<=z<16\)
\(n = 25y + z\), \(0<=z<25\)
Hence \(0<=z<16\), \(z = 0,1,2,3,4,....15\)
LCM of \(16\) & \(25\) is \(400\), hence \(n = 400w + z\)
So if \(z<10\), \(z\) will be units digit of a multiple of \(400\), hence the tens digit of \(n\) will be \(0\).
& if \(z>=10\), then last digit of 2 digit number \("z"\), will be the units digit of a multiple of \(400\) & the tens digit will be \(1\).
Hence 2 values for the remainder.
Statement 2 is Insufficient.
Answer A.
Thanks,
GyM