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# If n is an integer, when (2n + 2)^2 is divided by 4 the remainder is

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Math Expert
Joined: 02 Sep 2009
Posts: 59588
If n is an integer, when (2n + 2)^2 is divided by 4 the remainder is  [#permalink]

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15 Mar 2019, 00:26
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Difficulty:

5% (low)

Question Stats:

88% (00:51) correct 12% (01:45) wrong based on 52 sessions

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If n is a positive integer, when (2n + 2)^2 is divided by 4 the remainder is

(A) 0
(B) 1
(C) 2
(D) 3
(E) 4

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Joined: 31 Oct 2013
Posts: 1489
Concentration: Accounting, Finance
GPA: 3.68
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Re: If n is an integer, when (2n + 2)^2 is divided by 4 the remainder is  [#permalink]

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15 Mar 2019, 02:34
Bunuel wrote:
If n is a positive integer, when (2n + 2)^2 is divided by 4 the remainder is

(A) 0
(B) 1
(C) 2
(D) 3
(E) 4

Note: n is a positive integer.

(2n + 2) = even + even= even.

Set a minimum value.

n = 1.

2*1 + 2 = 4. when 4 is divided by 4 remainder is 0. It will be true for all cases.

The best answer s A .
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Joined: 19 Jan 2019
Posts: 110
Re: If n is an integer, when (2n + 2)^2 is divided by 4 the remainder is  [#permalink]

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15 Mar 2019, 02:53
1
Expand (2n+2)^2
4n^2 + 8n + 4... Each term is divisible by 4... Remainder will always be 0.

Alternatively plugging in Will also work..

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Re: If n is an integer, when (2n + 2)^2 is divided by 4 the remainder is  [#permalink]

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16 Mar 2019, 02:45
Bunuel wrote:
If n is a positive integer, when (2n + 2)^2 is divided by 4 the remainder is

(A) 0
(B) 1
(C) 2
(D) 3
(E) 4

for all values of n , in expression(2n + 2)^2
we get remainder as 0 when divided by 4
IMO A
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Joined: 10 Nov 2018
Posts: 84
Re: If n is an integer, when (2n + 2)^2 is divided by 4 the remainder is  [#permalink]

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17 Mar 2019, 01:55
(2n+2)^2 = 2^2 (n+1)^2 => 4 (n+1)^2

4(n+1)^2 divided by 4 will be (n+1)^2, hence remainder is 0
Re: If n is an integer, when (2n + 2)^2 is divided by 4 the remainder is   [#permalink] 17 Mar 2019, 01:55
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