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03 Aug 2018, 03:52
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If O is the center of the circle above and the length of arc RSP is twice the length of arc PQR, then x equals
(A) 60
(B) 100
(C) 120
(D) 150
(E) 240
Attachment:
Screen Shot 2015-03-10 at 1.53.19 PM.png [ 16.04 KiB | Viewed 4823 times ]
03 Aug 2018, 04:02
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Angle POR=x
Outside angle (maybe incorrect interpretation) POR=2x
x+2x=360
x=120
IMO
Ans: C
Outside angle (maybe incorrect interpretation) POR=2x
x+2x=360
x=120
IMO
Ans: C
03 Aug 2018, 07:56
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Bunuel
If O is the center of the circle above and the length of arc RSP is twice the length of arc PQR, then x equals
(A) 60
(B) 100
(C) 120
(D) 150
(E) 240
[/spoiler]
(A) 60
(B) 100
(C) 120
(D) 150
(E) 240
[/spoiler]
\(\widehat{PQR}\)+\(\widehat{RSP}\)=\(Circumference=2\pi*r\)
Or, \(\widehat{PQR}\)+2*\(\widehat{PQR}\)=\(2\pi*r\)
Or, 3*\(\widehat{PQR}\)=\(2\pi*r\)
Or, \(3*2\pi*r(x/360)\)=\(2\pi*r\)
Or, \(x=\frac{360}{3}\)
Or, x=120
Ans. (C)
