chetan2u wrote:

If only one of the three integers x, y and z is negative, is x>yz?

(1) \(\frac{x}{y}>z\)

(2) \(xy>0\)

New question

St1:-

\(x/y>z\)

This holds true when x and y are non-negative & z is negative.(y can't be zero).

Since magnitude of x,y and z are not known,We have to consider z as negative in order to validate the inequality.

So yz is negative.

Hence x>yz is true.

Sufficient.

St2:-

xy > 0

So both x and y are positive.

Question tells us that only one of x,y, and z is a negative integer.since st2 is not dependent on polarity and magnitude of z,hence,we can consider z as an integer(+/-/0).

So x>yz may or mayn't be true.

So insufficient.

And. A

P.S.-

chetan2u Sir, Request your kind perusal.

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Regards,

PKN

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