Solving for the 2 Absolute Value Inequalities:
I.
-(3) = p - 5 = +3
p = +8 ; OR ; p = +2
II.
-(5) = q - 3 = +5
q = +8 ; OR ; q = -(2)
WOTF MUST be True - if we find a Case in which the Statement can be FALSE, we Eliminate
A. p + q > 0
IF: p = +2 and q =-(2)
then this Statement is FALSE ---ELIMINATE
B. pq >/= 0
Same case as used in Answer A proves this Statement FALSE ---- ELIMINATE
C. [p] = [q]
IF: p = +2 and q = +8
Then this Statement is FALSE ---- ELIMINATE
D. [p] >/= [q]
Same Case as used in Answer C proves this Statement can be FALSE ---- ELIMINATE
By process of Elimination it must be E, but just to check:
E. -(6) </= p - q </= +10
p can equal = +8 OR +2
q can equal = +8 OR -(2)
(1st) the MAXIMUM Value of the Expression (p - q) is obtained when the Value of p is at its MAXIMUM Value and the Value of q is at its MINIMUM Value --- this happens where:
p = +8
q = (-)2
p - q = 8 - -(2) = 8 + 2 = +10
+10 is the MAXIMUM Value that (p - q) can take
therefore; (p - q) </= +10
(2nd)the MINIMUM Value of the Expression (p - q) occurs where the Value of p is at its MINIMUM and the Value of q is at its MAXIMUM --- this occurs where:
p = +2
q = +8
p - q = 2 - 8 = -(6)
-(6) is the MINIMUM Value that (p - q) can take
therefore: -(6) </= p - q
TOGETHER, -E- is proven that it must be TRUE:
-(6) </= p - q < /= + 10
-E-