Bunuel wrote:
If p and q are consecutive even integers and p < q, which of the following must be divisible by 3 ?
A. \(p^2 + pq\)
B. \(pq^2 + pq\)
C. \(p^2q – pq\)
D. \(p^2q^2\)
E. \(pq^2 – pq\)
Since p and q are consecutive even integers and since p < q, it must be true that q = p + 2. Let's evaluate each answer choice with this piece of information in mind:
Answer choice A: p^2 + pq
\(\Rightarrow\) p^2 + pq
\(\Rightarrow\) p(p + q)
\(\Rightarrow\) p(p + p + 2)
\(\Rightarrow\) p(2p + 4)
\(\Rightarrow\) 2p(p + 2)
This expression is not necessarily divisible by 3, for instance, if p = 2.
Answer choice B: pq^2 + pq
\(\Rightarrow\) pq^2 + pq
\(\Rightarrow\) pq(q + 1)
\(\Rightarrow\) p(p + 2)(p + 2 + 1)
\(\Rightarrow\) p(p + 2)(p + 3)
This expression is not necessarily divisible by 3, for instance, if p = 2.
Answer choice C: (p^2)q – pq
\(\Rightarrow\) (p^2)q - pq
\(\Rightarrow\) pq(p - 1)
\(\Rightarrow\) p(p + 2)(p - 1)
This expression is not necessarily divisible by 3, for instance, if p = 2.
Answer choice D: (p^2)(q^2)
\(\Rightarrow\) (p^2)(q^2)
\(\Rightarrow\) (p^2)(p + 2)^2
Once again, we can let p = 2 to obtain a number which is not divisible by 3. Thus, this expression is not divisible by 3 either.
Since we eliminated all answer choices besides E, the correct answer must be E. However, as an exercise, let's verify that the expression given in answer choice E must be divisible by 3.
Answer choice E: pq^2 - pq
\(\Rightarrow\) pq^2 - pq
\(\Rightarrow\) pq(q - 1)
\(\Rightarrow\) p(p + 2)(p + 2 - 1)
\(\Rightarrow\) p(p + 2)(p + 1)
We see that this expression is the product of three consecutive integers. Since the product of n consecutive integers is always divisible by n!, this expression is divisible by 3 for every value of p.
Answer: E