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If P is a prime number and Q is a positive integer, how many factors [#permalink]
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If P is a prime number and Q is a positive integer, how many factors does P^2*Q have? (1) The lowest number that has both P^2 and Q^3 as its factors is 5400 (2) P and Q have only one common factor
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Originally posted by sekharm2389 on 01 Mar 2018, 00:53.
Last edited by Bunuel on 01 Mar 2018, 01:10, edited 1 time in total.
Renamed the topic and edited the question.
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If P is a prime number and Q is a positive integer, how many factors [#permalink]
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If P is a prime number and Q is a positive integer, how many factors does P^2*Q have?(1) The lowest number that has both P^2 and Q^3 as its factors is 5400. This means that 5,400 is the least common multiple of P^2 (square of a prime) and Q^3 (perfect cube), so both P^2 and Q^3 are factors of 5,400. Factorize: \(5400 = 2^3*3^3*5^2\). P^2, which is a square of a prime, must be 5^2 (so P must be 5) because in any other case (say if P^2 is 2^2 or 3^2), the remaining multiple will not be a perfect square (Q^3). Therefore, \(P^2 = 5^2\) (P = 5) and \(Q^3 = 2^3*3^3\) (Q = 6). \(P^2*Q = 5^2*6 = 5^2*2*3\). The number of factors \(= (2 + 1)(1 + 1)(1 + 1) = 12\). Sufficient. (2) P and Q have only one common factor. This means that P and Q are co-prime, their only common factor is 1. This is clearly insufficient: for example, P could be 2 and Q could be 3, 3^2, 3^3, ... Answer: A. Hope it's clear.
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If P is a prime number and Q is a positive integer, how many factors [#permalink]
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09 Mar 2018, 09:15
Hi Bunuel, Why are we assuming P^2 and Q^3 are the only factors apart from 1 for the number 5400? I considered multiple possibilities for Q [2,3,6,1] so went with E. I think I am missing something in the reasoning. Can you help? Tx.
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Re: If P is a prime number and Q is a positive integer, how many factors [#permalink]
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09 Mar 2018, 10:01
srinjoy1990 wrote: Hi Bunuel,
Why are we assuming P^2 and Q^3 are the only factors apart from 1 for the number 5400?
I considered multiple possibilities for Q [2,3,6,1] so went with E. I think I am missing something in the reasoning. Can you help?
Tx. How can P^2 and Q^3 be the only factors of 5,400? A number to have four factors should be of the form prime1*prime2, in this case its factors would be 1, p1, p2, and p1*p2. If you say that Q can 1, 2, or 3, then what would P and would 5,400 be the LCM of P^2 an Q^3?
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Re: If P is a prime number and Q is a positive integer, how many factors [#permalink]
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09 Mar 2018, 11:03
Quote: (2) P and Q have only one common factor. This means that P and Q are co-prime, their only common factor is 1. This is clearly insufficient: for example, P could be 2 and Q could be 3, 3^2, 3^3, ... Are 2 prime numbers coprime? 2 and 7, for example. Thanks
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If P is a prime number and Q is a positive integer, how many factors [#permalink]
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09 Mar 2018, 11:06
Akela wrote: Quote: (2) P and Q have only one common factor. This means that P and Q are co-prime, their only common factor is 1. This is clearly insufficient: for example, P could be 2 and Q could be 3, 3^2, 3^3, ... Are 2 prime numbers coprime? 2 and 7, for example. Thanks Oh, I found the answer. Thanks!  Two integers a and b are said to be coprime if the only positive integer that evenly divides both of them is 1. That is, the only common positive factor of the two numbers is 1. So, according to the definition any two distinct primes are coprime.
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Re: If P is a prime number and Q is a positive integer, how many factors [#permalink]
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09 Mar 2018, 11:07
Akela wrote: Quote: (2) P and Q have only one common factor. This means that P and Q are co-prime, their only common factor is 1. This is clearly insufficient: for example, P could be 2 and Q could be 3, 3^2, 3^3, ... Are 2 prime numbers coprime? 2 and 7, for example. Thanks Two numbers are co-prime if they do not share any common factor but 1. So, any two different primes are co-prime. For example, 2 and 7 do not share any common factor but 1.
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Re: If P is a prime number and Q is a positive integer, how many factors [#permalink]
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09 Mar 2018, 11:52
Bunuel wrote: srinjoy1990 wrote: Hi Bunuel,
Why are we assuming P^2 and Q^3 are the only factors apart from 1 for the number 5400?
I considered multiple possibilities for Q [2,3,6,1] so went with E. I think I am missing something in the reasoning. Can you help?
Tx. How can P^2 and Q^3 be the only factors of 5,400? A number to have four factors should be of the form prime1*prime2, in this case its factors would be 1, p1, p2, and p1*p2. If you say that Q can 1, 2, or 3, then what would P and would 5,400 be the LCM of P^2 an Q^3? Thanks got my error. The only possible combination is 6^3*5^2 because, the numbers have to be coprime [The composite number cannot contain the prime number here], so the LCM is effectively product of the two. Should have noticed. 
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If P is a prime number and Q is a positive integer, how many factors [#permalink]
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10 Mar 2018, 11:33
Hi Bunuel,
Regarding 2nd statement ,since P and Q are coprime,I guess the number of factors will not change because if we take P=2 and Q=3 then number of factors for P^2Q will be (2+1)(1+1)=6 and if we take P=2 and Q=7 then also number of factors will remain same.Kindly let me know if i am missing anything.
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Re: If P is a prime number and Q is a positive integer, how many factors [#permalink]
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10 Mar 2018, 11:48
shu123 wrote: Hi Bunuel,
Regarding 2nd statement ,since P and Q are coprime,I guess the number of factors will not change because if we take P=2 and Q=3 then number of factors for P^2Q will be (2+1)(1+1)=6 and if we take P=2 and Q=7 then also number of factors will remain same.Kindly let me know if i am missing anything. First of all, please re-read this: (2) P and Q have only one common factor. This means that P and Q are co-prime, their only common factor is 1. This is clearly insufficient: for example, P could be 2 and Q could be 3, 3^2, 3^3, ...Next, try to pick P and Q so that they are co-prime but so that both are not primes. This should help.
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Re: If P is a prime number and Q is a positive integer, how many factors [#permalink]
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10 Mar 2018, 11:52
Oh ok..Thanks if i pick 7 and 9 ,no. of factors will vary.
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Re: If P is a prime number and Q is a positive integer, how many factors [#permalink]
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13 May 2018, 02:00
If P is a prime number and Q is a positive integer, how many factors does P^2*Q have? Statement 1:-
(1) The lowest number that has both P^2 and Q^3 as its factors is 5400.
This means that 5,400 is the LCM of P^2 (square of a prime) and Q^3 (perfect cube).
So both P^2 and Q^3 are factors of 5,400.
Factorize: \(5400 = 2^3*3^3*5^2\). P^2, which is a square of a prime, must be 5^2 (so P must be 5)
Therefore, \(P^2 = 5^2\) (P = 5)
And \(Q^3 = 2^3*3^3\) (Q = 6).
\(P^2*Q = 5^2*6 = 5^2*2*3\). The number of factors \(= (2 + 1)(1 + 1)(1 + 1) = 12\).
Sufficient.
Statement 2 :-
P and Q have only one common factor. This means that P and Q are co-prime,.
For example, P could be 2. Q could be 3, 3^2, 3^3, ... There is no data provided for Q.
This is clearly insufficient.
Answer: A.
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Re: If P is a prime number and Q is a positive integer, how many factors
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