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20 Jun 2016, 04:05
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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If P is an integer, is P|P| < \(2^P\) ?
(1) P<0
(2) \(P^2 -5P +6 = 0\)
(1) P<0
(2) \(P^2 -5P +6 = 0\)
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20 Jun 2016, 04:12
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I don't know the OA.
I am getting
a definite Yes for Statement (1)
and a definite No for Statement (2).
Please Help.
I am getting
a definite Yes for Statement (1)
and a definite No for Statement (2).
Please Help.
20 Jun 2016, 06:29
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1.If p < 0 and an integer then p can be
a. -ve , in that case P|P| will always be -ve and always less than 2^p
therefore sufficient
2.p^2-3p-2p+6=0
(p-3)(p-2)
p=2,3
for p=2
p|p|=4 and 2^2 =4 p|p| = 2^p
for p=3
p|p|=9 and 2^3 = 8 p|p| > 2^p
in both the cases p|p| is not less than 2^p
IMO D
same
a. -ve , in that case P|P| will always be -ve and always less than 2^p
therefore sufficient
2.p^2-3p-2p+6=0
(p-3)(p-2)
p=2,3
for p=2
p|p|=4 and 2^2 =4 p|p| = 2^p
for p=3
p|p|=9 and 2^3 = 8 p|p| > 2^p
in both the cases p|p| is not less than 2^p
IMO D
same
