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michaelny2001
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If p is an intiger, is p/18 an intiger? 23 Oct 2007, 17:15
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Could somebody please explain this one? The book does a very poor job in doing so.

If p is an intiger, is p/18 an intiger?

1. 5p/18 is an intiger
2. 6p/18 is an intiger

Thanks,



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If p is an intiger, is p/18 an intiger? 23 Oct 2007, 17:41
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is it A? I will post explanation if I'm correct.
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If p is an intiger, is p/18 an intiger? 23 Oct 2007, 18:55
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michaelny2001
Could somebody please explain this one? The book does a very poor job in doing so.

If p is an intiger, is p/18 an intiger?

1. 5p/18 is an intiger
2. 6p/18 is an intiger

Thanks,
Show more


A.

p/18 can only be an integer if p has the following factors: 2*3*3

(1) p = (I * 18)/5
Since p is defined as an integer, "I" can only be a multiple of 5 because 18 and 5 have no common factor. This means P is divisible by 18.
SUFFICIENT

(2) p = (I * 18)/6 = I * 3
If I = 2, p/18 is not an integer
If I = 6, p/18 is an integer
INSUFFICIENT
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GK_Gmat
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If p is an intiger, is p/18 an intiger? 23 Oct 2007, 22:10
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michaelny2001
Could somebody please explain this one? The book does a very poor job in doing so.

If p is an intiger, is p/18 an intiger?

1. 5p/18 is an intiger
2. 6p/18 is an intiger

Thanks,
Show more


A.

stat 1:
5*p/18 is an integer. Since 5 is not divisible by 18, the only way for 5p/18 to be an integer is if p is divisible by 18, meaning p/18 is an integer.
Suff.

stat 2:
6*p/18 = p/3 is an integer.
If p = 3 then p/3 is an int. but p/18 is not an int.
If p = 18 then p/3 is an int. and p/18 is an int.
Since we get two different answers, stat 2 is insuff.
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If p is an intiger, is p/18 an intiger? 24 Oct 2007, 08:28
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Thanks guys, it is A. I find it funny how it works, i guess i still have a long way to go... :-(
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illusion
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If p is an intiger, is p/18 an intiger? 25 Oct 2007, 21:26
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This is from MGMT CAT I did this evening. I came up with the same answer "A" ....but to my surprise, the test makers say the answer should be 'C' .....I am unable to refute their explanation. This is how they explain....
Accoding to statement 1....5n/18 is an integer. if we set this equation equal to the integer 1.
5n/18 = 1,
then n/18 = 1/5 . In this case n/18 is NOT an integer. so, statement 1 is not sufficient.

....just don't want to accept it. can some one explain.
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If p is an intiger, is p/18 an intiger? 25 Oct 2007, 21:43
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illusion
This is from MGMT CAT I did this evening. I came up with the same answer "A" ....but to my surprise, the test makers say the answer should be 'C' .....I am unable to refute their explanation. This is how they explain....
Accoding to statement 1....5n/18 is an integer. if we set this equation equal to the integer 1.
5n/18 = 1,
then n/18 = 1/5 . In this case n/18 is NOT an integer. so, statement 1 is not sufficient.

....just don't want to accept it. can some one explain.
Show more


not sure how this (bolded) can be the case. We cannot set 5p/18 = 1 because the only value of p for which this is true is 1/5. But from the stem we know that p can only be an integer.
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If p is an intiger, is p/18 an intiger? 06 Dec 2007, 16:27
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GK_Gmat
illusion
This is from MGMT CAT I did this evening. I came up with the same answer "A" ....but to my surprise, the test makers say the answer should be 'C' .....I am unable to refute their explanation. This is how they explain....
Accoding to statement 1....5n/18 is an integer. if we set this equation equal to the integer 1.
5n/18 = 1,
then n/18 = 1/5 . In this case n/18 is NOT an integer. so, statement 1 is not sufficient.

....just don't want to accept it. can some one explain.

not sure how this (bolded) can be the case. We cannot set 5p/18 = 1 because the only value of p for which this is true is 1/5. But from the stem we know that p can only be an integer.
Show more

The trick is that the question does not say that n is an integer. So 1/5 is actually okay.
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If p is an intiger, is p/18 an intiger? 06 Dec 2007, 17:01
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michaelny2001
Could somebody please explain this one? The book does a very poor job in doing so.

If p is an intiger, is p/18 an intiger?

1. 5p/18 is an intiger
2. 6p/18 is an intiger

Thanks,
Show more



1) P= integer. 5p/18= integer. 5p/3*2*3 so P must be divisible by 18. Suff.

2) 2*3*p/3*3*2 p could be 18 which the answer is YES or P could be 3 and the answer is NO. either way it suffices S2, but not our main stem.


A



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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