durgamadhab
amanvermagmat
If points A, B, C lie in the xy plane, is the area of triangle ABC greater than 6 square units?
(1) Equation of line AB is y=4 and equation of line BC is x=3.
(2) All three points A, B, C lie in first quadrant only.
Ans C: as axes do not come in any quadrant. As per both (1) and (2).... 0<x<=3 and 0<y<=4..... so area will be always less than 6 if the triangle lies in 1st quadrant
Hi
durgamadhab ,
Your point is correct. However, the following are the points to ponder:-
1. In order to form a triangle , we have to consider the point of intersection of the lines AB & BC one of the vertices of triangle ABC. So, 'B' is the fixed vertices with co-ordinates B(3,4).
2. The points A & C have to lie necessarily on the line AB & BC respectively. (otherwise st1 is not validated)
3. ABC is a right angled triangle in the 1st quadrant.(As per st2)
4. With a fixed B; 0<AB<3 & 0<BC< infinity (subject to \(AC^2=AB^2+BC^2\)) (extending line BC vertically upward, C tends to have infinite no of positions))
5. Area of right angled triangle=\(\frac{1}{2}*AB*BC\) can have more than one value of square units.
Hope this is sufficient to say our answer E.