Hey
Bunuel I hope you are doing fine. I have a silly question that I would like to see if you could please help me, if it makes no sense, then forgive me. I have tried this question several times over the course of many months and I always miss it since once I get to the equation 2s + r = 4, I always try to simplify it and end up doing a lot of math without really realizing that there is only 1 scenario that makes this equation possible (s=1 and r=2). I have always thought that I have learnt my lesson once I go over the answers, and I miss it again once I do it a few weeks later. Do you have any advice about what I can do so I can avoid this type of silly mistakes in the future?
Bunuel
If r and s are positive integers such that (2^r)(4^s) = 16, then 2r + s =
(A) 2
(B) 3
(C) 4
(D) 5
(E) 6