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If rectangle ABCD is inscribed in the circle above, what is the area

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If rectangle ABCD is inscribed in the circle above, what is the area  [#permalink]

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New post 26 Apr 2019, 01:34
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Re: If rectangle ABCD is inscribed in the circle above, what is the area  [#permalink]

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New post 26 Apr 2019, 12:52
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Bunuel wrote:
Image
If rectangle ABCD is inscribed in the circle above, what is the area of the circular region?

A. 36.00π
B. 42.25π
C. 64.00π
D. 84.50π
E. 169.00π


PS77502.01
OG2020 NEW QUESTION

Attachment:
2019-04-26_1231.png


Draw a line connecting points A and C.
Image
An important circle property (see video below for more info) tells us that, if we have a 90-degree inscribed angle, then that angle must be containing ("holding") the DIAMETER of the circle.
So, we know that AC = the diameter of the circle.


To find the hypotenuse of the red triangle, we can EITHER apply the Pythagorean Theorem OR recognize that 5 and 12 are part of the Pythagorean triplet 5-12-13
Image
With either approach, we learn that AC = 13

IMPORTANT: if the diameter (AC) is 13, then the radius = 13/2 = 6.5

What is the area of the circular region?
Area of circle = πr²
So, area = π(6.5²)
= 42.25π

Answer: B

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Re: If rectangle ABCD is inscribed in the circle above, what is the area  [#permalink]

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New post 26 Apr 2019, 10:05
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The rectangle is equally placed on the center of the circle.
Let O be the center of the circle.
And X be the midpoint of AB.
Then OX = 5/2 = 2/5 and XB = 12/2 = 6
Triangle OXB is a right angles triangle.
OB = radius = \(\sqrt{6^2+2.5^2} = \sqrt{42.5}\)

Area = \(π*r^2 = 42.5π\)

B is the answer.
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Re: If rectangle ABCD is inscribed in the circle above, what is the area  [#permalink]

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New post 27 Apr 2019, 05:23
diagonal of figure ; 13
so radis - 6.5
area = 6.5^2 * pi = 42.25 pi
IMO B
Bunuel wrote:
Image
If rectangle ABCD is inscribed in the circle above, what is the area of the circular region?

A. 36.00π
B. 42.25π
C. 64.00π
D. 84.50π
E. 169.00π


PS77502.01
OG2020 NEW QUESTION

Attachment:
2019-04-26_1231.png
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If rectangle ABCD is inscribed in the circle above, what is the area  [#permalink]

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New post Updated on: 22 May 2019, 09:51
Hi All,

We're told that a rectangle with sides of 5 and 12 is inscribed in the circle. We're asked for the area of the circular region. This question is based on a number of math patterns that can help you to save time answering the question.

First, any square or rectangle that is inscribed in a circle will have a diagonal that IS the diameter of the circle. Second, when splitting a rectangle or square across its diagonal, you'll form two right triangles. With the given side lengths of the rectangle (5 and 12), we have a 5/12/13 right triangle, so we know the diameter of the circle is 13. The radius is half the diameter... radius = 6.5

Area of a circle = (π)(R^2) = (π)(6.5^2)

At this point, you don't actually have to calculate the value. Since 6^2 = 36 and 7^2 = 49, we know the correct answer has to be between 36π and 49π. There's only one answer that fits...

Final Answer:

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Originally posted by EMPOWERgmatRichC on 27 Apr 2019, 16:57.
Last edited by EMPOWERgmatRichC on 22 May 2019, 09:51, edited 1 time in total.
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Re: If rectangle ABCD is inscribed in the circle above, what is the area  [#permalink]

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New post 01 May 2019, 00:03

Solution



Image

Given:
    • ABCD is a rectangle.

To Find:
    • Area of circle.

Approach and Working:


    • Since ABCD is a rectangle, \(AC^2\) = \(AB^2\) + \(BC^2\)
      o \(AC^2\) = \(12^2\) + \(5^2\) = 144 +25 = 169
         AC = 13

    • ∆ ABC is a right triangle and by applying the property that angle in a semi-circle is 90 degrees.
      o We can conclude that AC is the diameter of the triangle.
      o Hence, radius of circle = \(\frac{13}{2}\)

    • Therefore, area of circle = π * \((\frac{13}{2})^2\) = (\(\frac{169}{4}\)) π =42.25 π

Hence, option B is the correct answer.

Correct Answer: B
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Re: If rectangle ABCD is inscribed in the circle above, what is the area  [#permalink]

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New post 02 May 2019, 17:15
Bunuel wrote:
Image
If rectangle ABCD is inscribed in the circle above, what is the area of the circular region?

A. 36.00π
B. 42.25π
C. 64.00π
D. 84.50π
E. 169.00π

Attachment:
2019-04-26_1231.png


We see that diagonal AC (of the rectangle) is also the diameter of the circle. When we make diagonal AC, we see that we create a right triangle, and more specifically a 5-12-13 right triangle, so the length of AC is 13.

Since the diameter is 13, the radius is 6.5, and the area of the circle is (6.5)^2 x π = 42.25π.

Answer: B
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Re: If rectangle ABCD is inscribed in the circle above, what is the area  [#permalink]

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New post 29 May 2019, 13:20
Bunuel wrote:
Image
If rectangle ABCD is inscribed in the circle above, what is the area of the circular region?

A. 36.00π
B. 42.25π
C. 64.00π
D. 84.50π
E. 169.00π


PS77502.01
OG2020 NEW QUESTION

Attachment:
2019-04-26_1231.png


A good solution of the above question:

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Re: If rectangle ABCD is inscribed in the circle above, what is the area  [#permalink]

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New post 29 Jun 2019, 06:25
Diagonal of ABCD = 13 (Using Pythagoras theorem)

Hence, Diameter of circle = Diagonal = 13 | Radius = 6.5

Area of circle = pi * r^2 = pi * (13/2) * (13/2) = 42.25 pi
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Re: If rectangle ABCD is inscribed in the circle above, what is the area  [#permalink]

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New post 09 Oct 2019, 03:01
GMATPrepNow wrote:
Bunuel wrote:
Image
If rectangle ABCD is inscribed in the circle above, what is the area of the circular region?

A. 36.00π
B. 42.25π
C. 64.00π
D. 84.50π
E. 169.00π


PS77502.01
OG2020 NEW QUESTION

Attachment:
2019-04-26_1231.png


Draw a line connecting points A and C.
Image
An important circle property (see video below for more info) tells us that, if we have a 90-degree inscribed angle, then that angle must be containing ("holding") the DIAMETER of the circle.
So, we know that AC = the diameter of the circle.


To find the hypotenuse of the red triangle, we can EITHER apply the Pythagorean Theorem OR recognize that 5 and 12 are part of the Pythagorean triplet 5-12-13
Image
With either approach, we learn that AC = 13

IMPORTANT: if the diameter (AC) is 13, then the radius = 13/2 = 6.5

What is the area of the circular region?
Area of circle = πr²
So, area = π(6.5²)
= 42.25π

Answer: B

RELATED VIDEO FROM MY COURSE


can u plz clear this ?
the angle formed by diameter at circum is 90 degrees

but here we know angle is 90 degree so we are saying thtt chor di diamerter
so my qsn is ,is collary also true?
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Re: If rectangle ABCD is inscribed in the circle above, what is the area   [#permalink] 09 Oct 2019, 03:01
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