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If s,u, and v are positive integers and 2s=2u+2v
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Updated on: 20 Mar 2012, 00:17
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72% (00:38) correct 28% (00:46) wrong based on 326 sessions
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If s,u, and v are positive integers and 2s=2u+2v, which of the following must be true? i. s=u ii. u is not equal to v iii. s > v A. None B. I only C. II only D. III only E. II and III Could someone explain this question a bit
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Originally posted by dzodzo85 on 20 Mar 2012, 00:13.
Last edited by Bunuel on 20 Mar 2012, 00:17, edited 1 time in total.
Added the OA




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Re: If s,u, and v are positive integers and 2s=2u+2v
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20 Mar 2012, 00:23
dzodzo85 wrote: If s, u, and v are positive integers and 2s=2u+2v, which of the following must be true?
i. s=u ii. u is not equal to v iii. s > v
A. None B. I only C. II only D. III only E. II and III
Could someone explain this question a bit Notice two things: 1. we are asked to find out which of the following MUST be true, not COULD be true and 2. s, u, and v are positive integers. Given: 2s=2u+2v > s=u+v. Now, since s, u, and v are positive integers then s is more than either u or v, so I is never true and III is always true. As for II: it's not necessarily true, for example 4=2+2. So, we have that only option III must be true. Answer: D. Check Must or Could be True questions to practice: search.php?search_id=tag&tag_id=193Hope it helps.
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Re: If s,u, and v are positive integers and 2s=2u+2v
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16 Apr 2012, 00:51
Bunuel, Not sure what I am missing here!! s=u+v, why is S>V is always true? Can we not have 2=2+0? In that case S=V, Right?
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Re: If s,u, and v are positive integers and 2s=2u+2v
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16 Apr 2012, 00:53
ENAFEX wrote: Bunuel,
Not sure what I am missing here!!
s=u+v, why is S>V is always true?
Can we not have 2=2+0? In that case S=V, Right? ooppss!! Sorry guys just realised my mistake. 0 is neither positive nor negative. So for this question because it says s,u,v are positive integers, the above argument is not valid.
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Re: If s,u, and v are positive integers and 2s=2u+2v
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16 Apr 2012, 00:55
ENAFEX wrote: Bunuel,
Not sure what I am missing here!!
s=u+v, why is S>V is always true?
Can we not have 2=2+0? In that case S=V, Right? none if s,u and v can have value=0 as they are positive that is >0 hope this helps...!!
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Re: If s,u, and v are positive integers and 2s=2u+2v
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18 Jul 2012, 11:44
2s = 2u + 2v
2(3) =2(2) +2(1) 2(4)=2(2)+2(2)
from the above two instances , (i) s= u (NOT ALWAYS) (ii) u not equal to v (not always) (iii) s > v (ALWAYS)
you can plug in various values and see . the third statement holds true always.
Ans : D



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Re: If s,u, and v are positive integers and 2s=2u+2v
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19 Jul 2012, 03:38
If s,u, and v are positive integers and 2s=2u+2v, which of the following must be true? i. s=u ii. u is not equal to v iii. s > v i. There is no way we can conclude that s=u from the given information ii. There is no way we can conclude that u is not qual to v iii. 2s = 2u + 2v => s= u +v since u is positive so S will be greater than V so its True! Hence, Answer is D Hope it Helps!
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Re: If s,u, and v are positive integers and 2s=2u+2v
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09 Dec 2015, 07:16
I don't think this is an official question. There is a similar problem in OG 12, that says \(2^s = 2^u + 2^v\) Answer options are the same.
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Re: If s,u, and v are positive integers and 2s=2u+2v
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