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If square ABCD has area x^2 and line segment AE has length 4, and line

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If square ABCD has area x^2 and line segment AE has length 4, and line  [#permalink]

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New post 18 Jan 2018, 03:13
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A
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C
D
E

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  25% (medium)

Question Stats:

87% (01:43) correct 13% (01:49) wrong based on 54 sessions

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If square ABCD has area x^2 and line segment AE has length 4, and line segment AF has length 3, then what is the area of IGCH in terms of x ?

(A) 4x + 12
(B) 7x - 12
(C) x^2 - 24
(D) x^2 - 3 x + 12
(E) x^2 - 7 x + 12

Attachment:
2018-01-18_1411.png
2018-01-18_1411.png [ 5.31 KiB | Viewed 1192 times ]

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Re: If square ABCD has area x^2 and line segment AE has length 4, and line  [#permalink]

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New post 18 Jan 2018, 04:53
1
Bunuel wrote:
Image
If square ABCD has area x^2 and line segment AE has length 4, and line segment AF has length 3, then what is the area of IGCH in terms of x ?

(A) 4 x + 12
(B) 7 x - 12
(C) x^2 - 24
(D) x^2 - 3 x + 12
(E) x^2 - 7 x + 12

Attachment:
2018-01-18_1411.png


Since the calculation looks straightforward, we'll just do it.
This is a Precise approach.

As the area of square ABCD is x^2 its side has length x.
Then IH = x - AE = x - 4 and IG = x - AF = x - 3
So our area is (x-4)(x-3) which is answer (E).

Bunuel I assume that x2 in the question should be x^2?
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Re: If square ABCD has area x^2 and line segment AE has length 4, and line  [#permalink]

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New post 18 Jan 2018, 06:01
DavidTutorexamPAL wrote:
Bunuel wrote:
Image
If square ABCD has area x^2 and line segment AE has length 4, and line segment AF has length 3, then what is the area of IGCH in terms of x ?

(A) 4 x + 12
(B) 7 x - 12
(C) x^2 - 24
(D) x^2 - 3 x + 12
(E) x^2 - 7 x + 12

Attachment:
2018-01-18_1411.png


Since the calculation looks straightforward, we'll just do it.
This is a Precise approach.

As the area of square ABCD is x^2 its side has length x.
Then IH = x - AE = x - 4 and IG = x - AF = x - 3
So our area is (x-4)(x-3) which is answer (E).

Bunuel I assume that x2 in the question should be x^2?


Yes. Edited. Thank you for noticing.
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Re: If square ABCD has area x^2 and line segment AE has length 4, and line  [#permalink]

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New post 18 Jan 2018, 06:05
maybe a suggestion but: if experts solve this, could they wait till some people have posted their answers, or, at least encase their answer in spoiler tags?
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Re: If square ABCD has area x^2 and line segment AE has length 4, and line  [#permalink]

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New post 18 Jan 2018, 07:35
Bunuel wrote:
Image
If square ABCD has area x^2 and line segment AE has length 4, and line segment AF has length 3, then what is the area of IGCH in terms of x ?

(A) 4x + 12
(B) 7x - 12
(C) x^2 - 24
(D) x^2 - 3 x + 12
(E) x^2 - 7 x + 12

Attachment:
The attachment 2018-01-18_1411.png is no longer available
Attachment:
2018-01-18_1411.png
2018-01-18_1411.png [ 7.07 KiB | Viewed 855 times ]


Area of IGCH = Area of ABCD - ( Area of AEFI + Area of FIBG + Area of EIDH )

Or, Area of IGCH = \(x^2 - ( 12 + 4x - 12 + 3x - 12 )\)

Or, Area of IGCH = \(x^2 - 7 x + 12\), answer will be (E)


aeon86 wrote:
maybe a suggestion but: if experts solve this, could they wait till some people have posted their answers, or, at least encase their answer in spoiler tags?


Done , please solve this question now...

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Re: If square ABCD has area x^2 and line segment AE has length 4, and line  [#permalink]

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New post 20 Jan 2018, 07:32
Bunuel wrote:
Image
If square ABCD has area x^2 and line segment AE has length 4, and line segment AF has length 3, then what is the area of IGCH in terms of x ?

(A) 4x + 12
(B) 7x - 12
(C) x^2 - 24
(D) x^2 - 3 x + 12
(E) x^2 - 7 x + 12

Attachment:
2018-01-18_1411.png


Since the area of the square ABCD is x^2, we observe that both AB and AD must have length x.

Since AB = x = EG and AF = 3 = EI, then IG = EG - EI = x - 3.

Since AD = x = FH and AE = 4 = FI, then IH = FH - FI = x - 4.

Thus, the area of IGCH is:

(x - 3)(x - 4) = x^2 - 7x + 12

Answer: E
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Re: If square ABCD has area x^2 and line segment AE has length 4, and line   [#permalink] 20 Jan 2018, 07:32
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