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24 Jan 2014, 03:53
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
70% (01:11) correct
30%
(01:29)
wrong
based on 3961
sessions
History
Date
Time
Result
Not Attempted Yet
If (t- 8) is a factor of t^2 - kt - 48, then k=
(A) - 6
(B) - 2
(C) 2
(D) 6
(E) 14
(A) - 6
(B) - 2
(C) 2
(D) 6
(E) 14
24 Jan 2014, 03:53
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SOLUTION
If (t- 8) is a factor of t^2 - kt - 48, then k=
(A) - 6
(B) - 2
(C) 2
(D) 6
(E) 14
\((t - 8)\) is a factor of \(t^2 - kt - 48\) means that \(t = 8\) is a solution of the equation \(t^2 - kt - 48 = 0\).
Substitute \(t = 8\) to get the value of k: \(8^2 - 8k - 48 = 0\) --> \(k = 2\).
Answer: C.
If (t- 8) is a factor of t^2 - kt - 48, then k=
(A) - 6
(B) - 2
(C) 2
(D) 6
(E) 14
\((t - 8)\) is a factor of \(t^2 - kt - 48\) means that \(t = 8\) is a solution of the equation \(t^2 - kt - 48 = 0\).
Substitute \(t = 8\) to get the value of k: \(8^2 - 8k - 48 = 0\) --> \(k = 2\).
Answer: C.
Updated on: 01 Nov 2014, 03:02
Originally posted by arunspanda on 25 Jan 2014, 00:46.
Last edited by arunspanda on 01 Nov 2014, 03:02, edited 1 time in total.
Last edited by arunspanda on 01 Nov 2014, 03:02, edited 1 time in total.
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If (t- 8) is a factor of \(t^2 - kt - 48\), then k=
(A) - 6
(8) - 2
(C) 2
(0) 6
(E) 14
It is given that \((t - 8)\) is a factor of the quadratic expression \(t^2 - kt - 48\)
Hence, we need to find the other factor of \(-48\) such that the sum of factors is\(-(\frac{-k}{1})=k\).
Thus, \((8) * x = -48\)
Or, \(x = -6\)
So, \(k = 8 + (- 6) = 2\)
Answer: (C)
(A) - 6
(8) - 2
(C) 2
(0) 6
(E) 14
It is given that \((t - 8)\) is a factor of the quadratic expression \(t^2 - kt - 48\)
Hence, we need to find the other factor of \(-48\) such that the sum of factors is\(-(\frac{-k}{1})=k\).
Thus, \((8) * x = -48\)
Or, \(x = -6\)
So, \(k = 8 + (- 6) = 2\)
Answer: (C)
