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HKD1710
If the altitude of a triangle increases by 6% and the base of the triangle increases by 8%, by what percent will the area of the triangle increase?

A) 6%

B) 8%

C) 7.24%

D) 14.48%

E) 48%

Percentage increase in the area of the triangle will be -

= \(6 + 8 + \frac{(6*8)}{100}\)

= \(14 + 0.48\)

= \(14.48\)

Thus, answer must be (D) 14.48 %
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HKD1710
If the altitude of a triangle increases by 6% and the base of the triangle increases by 8%, by what percent will the area of the triangle increase?

A) 6%

B) 8%

C) 7.24%

D) 14.48%

E) 48%

Percentage increase in the area of the triangle will be -

= \(6 + 8 + \frac{(6*8)}{100}\)

= \(14 + 0.48\)

= \(14.48\)

Thus, answer must be (D) 14.48 %

Can you explain how do we arrive at 6+8+fraction.. ..the concept
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HKD1710
If the altitude of a triangle increases by 6% and the base of the triangle increases by 8%, by what percent will the area of the triangle increase?

A) 6%

B) 8%

C) 7.24%

D) 14.48%

E) 48%

base triangle area=.5*1*1=.5
enlarged triangle area=.5*1.06*1.08=.5724
.5724/.5=1.1448=14.48% increase
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HKD1710
If the altitude of a triangle increases by 6% and the base of the triangle increases by 8%, by what percent will the area of the triangle increase?

A) 6%

B) 8%

C) 7.24%

D) 14.48%

E) 48%

We can let the original base = b and the original altitude = a, and thus the original area is ab/2.

The new altitude is 1.06a and the new base is 1.08b, so the new area is 1.1448ab/2. The new area is 1.1448, or equivalently, 114.48% times the old area. Therefore, the area increased 114.48 - 100 = 14.48%.

Answer: D
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