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Bunuel
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If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th 30 Aug 2018, 00:32
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A
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15% (low)

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85% (01:06) correct 15% (01:10) wrong based on 53 sessions

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If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is the average of a, b, c, and 13?

(A) 8
(B) 8.5
(C) 9
(D) 9.5
(E) It cannot be determined from the information given.
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A
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If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th 30 Aug 2018, 00:54
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a+b+c+5+6=5*6
-> a+b+c = 19
-> a+b+c+13 = 32
-> (a+b+c+13)/ 4 = 32/4 = 8, hence option (A)
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If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th 30 Aug 2018, 01:04
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very basic question.

(a+b+c+5+6)/5=6, so a+b+c=19.

(a+b+c+13)/4=(19+13)/4=8

ANS.A
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If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th 30 Aug 2018, 01:09
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Bunuel
If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is the average of a, b, c, and 13?

(A) 8
(B) 8.5
(C) 9
(D) 9.5
(E) It cannot be determined from the information given.

Given, a+b+c+5+6=5*6=30
Or, a+b+c+5+6+2=30+2=32
Or, \(\frac{a+b+c+13}{4}=\frac{32}{4}=8\)
Or, average of a, b, c, and 13 is 8

Ans. (A)
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If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th 30 Aug 2018, 06:14
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Bunuel
If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is the average of a, b, c, and 13?

(A) 8
(B) 8.5
(C) 9
(D) 9.5
(E) It cannot be determined from the information given.


\(\frac{a + b + c + d + 5 + 6}{5 = 6}\)

a + b + c + d + 11 = 30

a + b + c = 19

a + b + c + 13 / 4

\(\frac{19 + 13}{4}\)

= \(\frac{32}{4}\)

= 8

The best answer is A.
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If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th 30 Aug 2018, 07:12
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Bunuel
If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is the average of a, b, c, and 13?

(A) 8
(B) 8.5
(C) 9
(D) 9.5
(E) It cannot be determined from the information given.
\(a + b + c + 5 + 6 = 30\)

So, \(a + b + c = 19\)

So, the average of a, b, c, and 13 = \(\frac{19 + 13}{4} = 8\) Answer must be (A)
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If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th 04 Sep 2018, 04:38
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Bunuel
If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is the average of a, b, c, and 13?

(A) 8
(B) 8.5
(C) 9
(D) 9.5
(E) It cannot be determined from the information given.


We can create the equation:

(a + b + c + 5 + 6)/5 = 6

a + b + c + 11 = 30

a + b + c = 19

So the average of a, b, c, and 13 is:

(a + b + c + 13)/4

(19 + 13)/4

32/4 = 8

Answer: A
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If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th 05 Aug 2022, 23:54
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Theory

    ➡ Average = Sum of all the Values / Total Number of Values

The average (arithmetic mean) of a, b, c, 5, and 6 is 6

Average = \(\frac{Sum}{5}\) = \(\frac{a + b + c + 5 + 6 }{5}\) = \(\frac{a + b + c + 11}{5}\) = 6 (given)
a + b + c + 11 = 6*5 = 30
=> a + b + c = 30 - 11 = 19

The average of a, b, c, and 13

Average = \(\frac{Sum}{4}\) = \(\frac{a + b + c + 13 }{4}\) = \(\frac{19 + 13}{4}\) = \(\frac{32}{4}\) = 8

So, Answer will be A.
Hope it helps!

Watch the following video to Learn the Basics of Statistics

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