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If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th
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If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is the average of a, b, c, and 13?
(A) 8
(B) 8.5
(C) 9
(D) 9.5
(E) It cannot be determined from the information given.
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Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th
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a+b+c+5+6=5*6
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Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th
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very basic question.
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Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th
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Bunuel wrote:
If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is the average of a, b, c, and 13?
Given, a+b+c+5+6=5*6=30
Or, a+b+c+5+6+2=30+2=32
Or, \(\frac{a+b+c+13}{4}=\frac{32}{4}=8\)
Or, average of a, b, c, and 13 is 8
Ans. (A)
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Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th
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Bunuel wrote:
If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is the average of a, b, c, and 13?
\(\frac{a + b + c + d + 5 + 6}{5 = 6}\)
a + b + c + d + 11 = 30
a + b + c = 19
a + b + c + 13 / 4
\(\frac{19 + 13}{4}\)
= \(\frac{32}{4}\)
= 8
The best answer is A.
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Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th
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Bunuel wrote:
If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is the average of a, b, c, and 13?
\(a + b + c + 5 + 6 = 30\)
So, \(a + b + c = 19\)
So, the average of a, b, c, and 13 = \(\frac{19 + 13}{4} = 8\) Answer must be (A) _________________
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Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th
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Bunuel wrote:
If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is the average of a, b, c, and 13?
We can create the equation:
(a + b + c + 5 + 6)/5 = 6
a + b + c + 11 = 30
a + b + c = 19
So the average of a, b, c, and 13 is:
(a + b + c + 13)/4
(19 + 13)/4
32/4 = 8
Answer: A
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Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th &nbs
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79% (00:59) correct 
