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# If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th

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If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th  [#permalink]

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29 Aug 2018, 23:32
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If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is the average of a, b, c, and 13?

(A) 8
(B) 8.5
(C) 9
(D) 9.5
(E) It cannot be determined from the information given.

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Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th  [#permalink]

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29 Aug 2018, 23:54
a+b+c+5+6=5*6
-> a+b+c = 19
-> a+b+c+13 = 32
-> (a+b+c+13)/ 4 = 32/4 = 8, hence option (A)
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Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th  [#permalink]

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30 Aug 2018, 00:04
very basic question.

(a+b+c+5+6)/5=6, so a+b+c=19.

(a+b+c+13)/4=(19+13)/4=8

ANS.A
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Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th  [#permalink]

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30 Aug 2018, 00:09
Bunuel wrote:
If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is the average of a, b, c, and 13?

(A) 8
(B) 8.5
(C) 9
(D) 9.5
(E) It cannot be determined from the information given.

Given, a+b+c+5+6=5*6=30
Or, a+b+c+5+6+2=30+2=32
Or, $$\frac{a+b+c+13}{4}=\frac{32}{4}=8$$
Or, average of a, b, c, and 13 is 8

Ans. (A)
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Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th  [#permalink]

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30 Aug 2018, 05:14
Bunuel wrote:
If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is the average of a, b, c, and 13?

(A) 8
(B) 8.5
(C) 9
(D) 9.5
(E) It cannot be determined from the information given.

$$\frac{a + b + c + d + 5 + 6}{5 = 6}$$

a + b + c + d + 11 = 30

a + b + c = 19

a + b + c + 13 / 4

$$\frac{19 + 13}{4}$$

= $$\frac{32}{4}$$

= 8

The best answer is A.
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Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th  [#permalink]

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30 Aug 2018, 06:12
Bunuel wrote:
If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is the average of a, b, c, and 13?

(A) 8
(B) 8.5
(C) 9
(D) 9.5
(E) It cannot be determined from the information given.

$$a + b + c + 5 + 6 = 30$$

So, $$a + b + c = 19$$

So, the average of a, b, c, and 13 = $$\frac{19 + 13}{4} = 8$$ Answer must be (A)
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Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th  [#permalink]

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04 Sep 2018, 03:38
Bunuel wrote:
If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is the average of a, b, c, and 13?

(A) 8
(B) 8.5
(C) 9
(D) 9.5
(E) It cannot be determined from the information given.

We can create the equation:

(a + b + c + 5 + 6)/5 = 6

a + b + c + 11 = 30

a + b + c = 19

So the average of a, b, c, and 13 is:

(a + b + c + 13)/4

(19 + 13)/4

32/4 = 8

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Re: If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th   [#permalink] 04 Sep 2018, 03:38
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# If the average (arithmetic mean) of a, b, c, 5, and 6 is 6, what is th

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