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# If the average (arithmetic mean) of n and 11 is equal to 2n, what is

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Joined: 02 Sep 2009
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If the average (arithmetic mean) of n and 11 is equal to 2n, what is  [#permalink]

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26 Aug 2018, 21:20
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25% (medium)

Question Stats:

90% (00:58) correct 10% (00:42) wrong based on 49 sessions

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If the average (arithmetic mean) of n and 11 is equal to 2n, what is the average of n and $$\frac{13}{3}$$?

(A) 4
(B) 8
(C) 11
(D) 14
(E) 19

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Re: If the average (arithmetic mean) of n and 11 is equal to 2n, what is  [#permalink]

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26 Aug 2018, 21:32
Bunuel wrote:
If the average (arithmetic mean) of n and 11 is equal to 2n, what is the average of n and $$\frac{13}{3}$$?

(A) 4
(B) 8
(C) 11
(D) 14
(E) 19

First we have to find out the value of n.
Given, average (arithmetic mean) of n and 11 is equal to 2n
Or, $$\frac{n+11}{2}=2n$$
Or, n+11=4n
Or, 3n=11
Or, $$n=\frac{11}{3}$$

Average of n and $$\frac{13}{3}$$=Average of $$\frac{11}{3}$$ and $$\frac{13}{3}$$=$$\frac{\frac{11}{3}+\frac{13}{3}}{2}$$=$$\frac{8}{2}=4$$

Ans. (A)
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Re: If the average (arithmetic mean) of n and 11 is equal to 2n, what is  [#permalink]

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26 Aug 2018, 21:51
From what is given :
(n+11)/2 = 2n
n = 11/3

Average of n and 13/3:

(11/3 + 13/3)/2 = 8/2 = 4

IMO A.
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Re: If the average (arithmetic mean) of n and 11 is equal to 2n, what is  [#permalink]

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27 Aug 2018, 04:58
4
Bunuel wrote:
If the average (arithmetic mean) of n and 11 is equal to 2n, what is the average of n and $$\frac{13}{3}$$?

(A) 4
(B) 8
(C) 11
(D) 14
(E) 19

n +11/2=2n
n=11/3

n+13/3/2=3n+ 13/6

-substituting value of n
we get average of n and 13/2 =4

Correct ans:A
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Re: If the average (arithmetic mean) of n and 11 is equal to 2n, what is  [#permalink]

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27 Aug 2018, 05:07
n+11/2=2n
n=11/3

Now substituting it
n+13/3/2=?
11/3+13/3/2 = 24/3/2
Ans= 4(option A)
Re: If the average (arithmetic mean) of n and 11 is equal to 2n, what is   [#permalink] 27 Aug 2018, 05:07
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