GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 16 Oct 2019, 00:09

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Find Similar Topics 
Intern
Intern
avatar
Joined: 25 Sep 2010
Posts: 12
If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and  [#permalink]

Show Tags

New post 19 Oct 2010, 00:58
21
00:00
A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

65% (01:43) correct 35% (01:46) wrong based on 449 sessions

HideShow timer Statistics

If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and 11 is equal to the median of five numbers, what is the value of X

(1) 7 < x < 11
(2) x is the median of the five numbers

first statement is definitely sufficient, but in the second statement, if X is the median, it can take three numbers, 10. 9, 8, so ...how is it sufficient, i might be missing some basic point here,,,,so need help,,,,as the second statement is also sufficient for this problem
Most Helpful Expert Reply
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 58364
Re: If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and  [#permalink]

Show Tags

New post 20 Oct 2010, 08:46
7
5
vitamingmat wrote:
satishreddy wrote:
if the average arithmetic mean of the five numbers X, 7,2,16.11 is equal to the median of five numbers, what is the value of X

1) 7<X<11
2) X is the median of five numbers

first statement is definitely sufficient, but in the second statement, if X is the median, it can take three numbers, 10. 9, 8, so ...how is it sufficient, i might be missing some basic point here,,,,so need help,,,,as the second statement is also sufficient for this problem


I am not convinced with the above answers...

from 1 ) 7 < X< 11 === > X is like 7.1, or 7.2 or 7.5 or 8,8.1 or 9 0r 9.5 ...

there are so many possibilites so i can not take only 8,9,10 as X

so i can not decide from 1

from 2) X is the median of five numbers then === > X, 7,2,16,11 ....

==> how can i arrange if i dont know the value of X in either descending or ascending..

so from the both also it wont be possible to get the ans i believe...
So ans E ...

Do let me know if i am wrong....


There is one more thing we know from the stem: "the average arithmetic mean of the five numbers x, 7, 2, 16, 11 is equal to the median of five numbers" --> \(\frac{x+2+7+11+16}{5}=median\). As there are odd number of terms then the median is the middle term when arranged in ascending (or descending) order but we don't know which one (median could be x, 7 or 11).

(1) 7 < x < 11 --> when ordered we'll get 2, 7, x, 11, 16 --> \(\frac{x+2+7+11+16}{5}=median=x\) --> \(\frac{x+36}{5}=x\) --> \(x=9\). Sufficient.

(2) x is the median of five numbers --> the same info as above: \(\frac{x+2+7+11+16}{5}=median=x\) --> \(\frac{x+36}{5}=x\) --> \(x=9\). Sufficient.

Answer: D.
_________________
General Discussion
Manager
Manager
User avatar
Joined: 08 Sep 2010
Posts: 150
Location: India
WE 1: 6 Year, Telecom(GSM)
Re: If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and  [#permalink]

Show Tags

New post 19 Oct 2010, 03:22
1
satishreddy wrote:
if the average arithmetic mean of the five numbers X, 7,2,16.11 is equal to the median of five numbers, what is the value of X

1) 7<X<11
2) X is the median of five numbers

first statement is definitely sufficient, but in the second statement, if X is the median, it can take three numbers, 10. 9, 8, so ...how is it sufficient, i might be missing some basic point here,,,,so need help,,,,as the second statement is also sufficient for this problem



For finding out median you have to arrange the numbers in increasing or decresing order, then only you have to take the middle term as median.
So now the order will be 2,7,x,11,16
And in that way ,you will have the same median value i.e, 9.

So answer is D.


Please consider KUDOS if it is helpful to u .
Manager
Manager
avatar
Joined: 25 Aug 2010
Posts: 55
Re: If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and  [#permalink]

Show Tags

New post 20 Oct 2010, 06:24
satishreddy wrote:
if the average arithmetic mean of the five numbers X, 7,2,16.11 is equal to the median of five numbers, what is the value of X

1) 7<X<11
2) X is the median of five numbers

first statement is definitely sufficient, but in the second statement, if X is the median, it can take three numbers, 10. 9, 8, so ...how is it sufficient, i might be missing some basic point here,,,,so need help,,,,as the second statement is also sufficient for this problem


I am not convinced with the above answers...

from 1 ) 7 < X< 11 === > X is like 7.1, or 7.2 or 7.5 or 8,8.1 or 9 0r 9.5 ...

there are so many possibilites so i can not take only 8,9,10 as X

so i can not decide from 1

from 2) X is the median of five numbers then === > X, 7,2,16,11 ....

==> how can i arrange if i dont know the value of X in either descending or ascending..

so from the both also it wont be possible to get the ans i believe...
So ans E ...

Do let me know if i am wrong....
Intern
Intern
avatar
Joined: 20 Sep 2013
Posts: 2
Re: If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and  [#permalink]

Show Tags

New post 25 Sep 2013, 03:52
1
1) allow us to say that the first and last numbers of the series are 2 and 16 giving an average = 9 and, therefore, a median = 9.
giving that x must be a value between 8, 9, 10 we came to the conclusion that x=9 -> sufficient
2) the information that x=median therefore x=average is sufficient to allow to conclude that x=9. This information, in fact allow to exclude x<2 and x>16 and at the same time provide indications that the value is somewhere between the second and 4th value of the series.
Manager
Manager
avatar
B
Joined: 31 Mar 2013
Posts: 60
Location: India
GPA: 3.02
Re: If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and  [#permalink]

Show Tags

New post 09 Oct 2013, 11:17
3
The above set is not evenly spaced. Is it possible to have a non-evenly spaced set where \(mean=median\)?

Thank you for your help.
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 58364
Re: If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and  [#permalink]

Show Tags

New post 10 Oct 2013, 02:43
2
2
Current Student
avatar
Status: Difficult Roads often lead to beautiful destinations !!!
Joined: 29 Jul 2015
Posts: 14
Location: India
Concentration: Strategy, General Management
Schools: Ivey '19 (A$)
GMAT 1: 660 Q49 V32
GPA: 3.7
WE: Supply Chain Management (Consulting)
Re: If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and  [#permalink]

Show Tags

New post 29 Mar 2016, 12:07
Dear Bunuel , I have a doubt on statement B

Statement B says - x is the median of the 5 no's. So x can be 7,8,9,10,11 . Then how can we determine the value of x using B alone ?
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 58364
Re: If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and  [#permalink]

Show Tags

New post 29 Mar 2016, 12:19
3
ThePlayer wrote:
Dear Bunuel , I have a doubt on statement B

Statement B says - x is the median of the 5 no's. So x can be 7,8,9,10,11 . Then how can we determine the value of x using B alone ?


This is explained above: if-the-average-arithmetic-mean-of-the-five-numbers-x-103134.html#p803613

There is one more thing we know from the stem: "the average arithmetic mean of the five numbers x, 7, 2, 16, 11 is equal to the median of five numbers" --> \(\frac{x+2+7+11+16}{5}=median\). As there are odd number of terms then the median is the middle term when arranged in ascending (or descending) order but we don't know which one (median could be x, 7 or 11).
(1) 7 < x < 11 --> when ordered we'll get 2, 7, x, 11, 16 --> \(\frac{x+2+7+11+16}{5}=median=x\) --> \(\frac{x+36}{5}=x\) --> \(x=9\). Sufficient.

(2) x is the median of five numbers --> the same info as above: \(\frac{x+2+7+11+16}{5}=median=x\) --> \(\frac{x+36}{5}=x\) --> \(x=9\). Sufficient.

Answer: D.
_________________
Board of Directors
User avatar
P
Joined: 17 Jul 2014
Posts: 2514
Location: United States (IL)
Concentration: Finance, Economics
GMAT 1: 650 Q49 V30
GPA: 3.92
WE: General Management (Transportation)
GMAT ToolKit User Reviews Badge
Re: If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and  [#permalink]

Show Tags

New post 09 Apr 2016, 13:54
oh man..I just had this question in my GMATPrep test, and I panicked and picked A...
quick question to Bunuel, can we consider only INTEGER values, knowing that the question stem tells that we have NUMBERS (aka any numbers)?

1. x has values 8, 9, 10.
we know that (36+x)/5 = x
36+x=5x
x=9
so only value if x=9

2. x is the median of the five
36+x=5x
x=9
yes, 9 is the median.

D

I dismissed B because I considered non-integer values for x...but still..illogical..because if we apply what we are given..we always get x=9...
Manager
Manager
avatar
G
Joined: 26 Dec 2015
Posts: 236
Location: United States (CA)
Concentration: Finance, Strategy
WE: Investment Banking (Venture Capital)
Re: If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and  [#permalink]

Show Tags

New post 16 Sep 2017, 16:48
If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and 11 is equal to the median of five numbers, what is the value of X

(1) 7 < x < 11
(2) x is the median of the five numbers


Important to note: This is a purely CONCEPTUAL problem. Meaning, there's HARDLY ANY MATH REQUIRED/INVOLVED. You should be able to eye this and take 30-45 seconds MAX. I'll show you how.

1- set up #s in increasing order (common step whenever you see the word "median"): 2, 7, 11, 16, x --> quickly see 2+7=9...9+11=20, 20+16=36.
2- average = \(\frac{sum of #s in a set}{total numbers in a set}\) --> \(\frac{36+x}{5}\)
3- set up question: \(\frac{36+x}{5}\) = median.
> key here is to find out what x is (or what the median is)!

1) TELLS US X=MEDIAN! How do you know this? Well, there are 5 terms in the set.
> 2 terms are BELOW 7.
> 2 terms are ABOVE 11.
-- Since there are only 5 terms in a set, the 3rd term (middle) = median. Bingo. Eliminate B, C, E.

2) SAME AS 1!
-- Elim A.

Ans: D
Intern
Intern
avatar
B
Joined: 10 May 2017
Posts: 5
Re: If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and  [#permalink]

Show Tags

New post 18 Oct 2017, 01:37
Bunuel wrote:
andrewwal wrote:
russ9

1) I believe that it can also be 11 since if x was 11 the median in fact would be 11 (but the median could never be 16 since if x=16, then you'd have 2, 7, 11, 16, 16 and the median would be 11 not 16).

2) Statement 1 and 2 are essentially saying the say thing, since the constraint "the mean is equal to the median" and that is the only value [9] that satisfies that constraint -- therefore it is D.

Please Kudos if this helped!


Correct. 15 was a typo there. Edited.

Bunuel
Hi Bunuel,
I understood the solution however,
Elementary doubt here. Since Mean=Median, Shouldn't the numbers in the set be consecutive, However I cannot seem understand the consecutive nature of the above mentioned set.
Thanks
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 58364
Re: If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and  [#permalink]

Show Tags

New post 18 Oct 2017, 01:48
neilphilip10 wrote:
Bunuel
Hi Bunuel,
I understood the solution however,
Elementary doubt here. Since Mean=Median, Shouldn't the numbers in the set be consecutive, However I cannot seem understand the consecutive nature of the above mentioned set.
Thanks


For an evenly spaced set (arithmetic progression), the median equals to the mean. Though the reverse is not necessarily true. Consider {0, 1, 1, 2} --> median = mean = 1 but the set is not evenly spaced.
_________________
Intern
Intern
avatar
B
Joined: 05 Mar 2015
Posts: 41
Location: Azerbaijan
GMAT 1: 530 Q42 V21
GMAT 2: 600 Q42 V31
GMAT 3: 700 Q47 V38
Re: If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and  [#permalink]

Show Tags

New post 22 May 2018, 12:05
Hi, I just found a mistake in a question and would like to let you know

You can answer the question even without looking at the statements 1 and 2 - the question stem itself gives sufficient information to find the value of x, which is 9

My reasoning:

if we order the numbers in an increasing order we get 2, 7, 11, 16. we also have x. Regardless of the value of x, the median will be a number that is 7≤X ≤11

The question also says that median equals the mean. (36+x)/5 is the mean, which is also median. (36+x)/5 this tells us that x cannot be 7, because 36/5 is already greater than 7. If x were 7 the median would not be equal to the mean.

If x were 8, the median would be 8, but the mean would be greater than mean. You can check all numbers that satisfies 7≤X ≤11. The only number that satisfies 7≤X ≤11 and also makes median equal to the mean is 9


You can answer the question without looking at the statements
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 58364
Re: If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and  [#permalink]

Show Tags

New post 23 May 2018, 05:58
kablayi wrote:
Hi, I just found a mistake in a question and would like to let you know

You can answer the question even without looking at the statements 1 and 2 - the question stem itself gives sufficient information to find the value of x, which is 9

My reasoning:

if we order the numbers in an increasing order we get 2, 7, 11, 16. we also have x. Regardless of the value of x, the median will be a number that is 7≤X ≤11

The question also says that median equals the mean. (36+x)/5 is the mean, which is also median. (36+x)/5 this tells us that x cannot be 7, because 36/5 is already greater than 7. If x were 7 the median would not be equal to the mean.

If x were 8, the median would be 8, but the mean would be greater than mean. You can check all numbers that satisfies 7≤X ≤11. The only number that satisfies 7≤X ≤11 and also makes median equal to the mean is 9


You can answer the question without looking at the statements


That's not correct.

From the stem, x can be -1, 9 or 19.

If x = -1, then the set is {-1, 2, 7, 11, 16} --> median = mean = 7.
If x = 9, then the set is {-2, 7, 9, 11, 16} --> median = mean = 9.
If x = 19, then the set is {2, 7, 11, 16, 19} --> median = mean = 11.
_________________
Intern
Intern
avatar
B
Joined: 11 Feb 2019
Posts: 12
Re: If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and  [#permalink]

Show Tags

New post 28 Mar 2019, 08:04
Does this question even need any of the answer choices?

As in, this question can be answered without using either of the two options.

Is there any other question type where value of x needs to be calculated in series where the answer choices really are needed?


Bunuel wrote:
vitamingmat wrote:
satishreddy wrote:
if the average arithmetic mean of the five numbers X, 7,2,16.11 is equal to the median of five numbers, what is the value of X

1) 7<X<11
2) X is the median of five numbers

first statement is definitely sufficient, but in the second statement, if X is the median, it can take three numbers, 10. 9, 8, so ...how is it sufficient, i might be missing some basic point here,,,,so need help,,,,as the second statement is also sufficient for this problem


I am not convinced with the above answers...

from 1 ) 7 < X< 11 === > X is like 7.1, or 7.2 or 7.5 or 8,8.1 or 9 0r 9.5 ...

there are so many possibilites so i can not take only 8,9,10 as X

so i can not decide from 1

from 2) X is the median of five numbers then === > X, 7,2,16,11 ....

==> how can i arrange if i dont know the value of X in either descending or ascending..

so from the both also it wont be possible to get the ans i believe...
So ans E ...

Do let me know if i am wrong....


There is one more thing we know from the stem: "the average arithmetic mean of the five numbers x, 7, 2, 16, 11 is equal to the median of five numbers" --> \(\frac{x+2+7+11+16}{5}=median\). As there are odd number of terms then the median is the middle term when arranged in ascending (or descending) order but we don't know which one (median could be x, 7 or 11).

(1) 7 < x < 11 --> when ordered we'll get 2, 7, x, 11, 16 --> \(\frac{x+2+7+11+16}{5}=median=x\) --> \(\frac{x+36}{5}=x\) --> \(x=9\). Sufficient.

(2) x is the median of five numbers --> the same info as above: \(\frac{x+2+7+11+16}{5}=median=x\) --> \(\frac{x+36}{5}=x\) --> \(x=9\). Sufficient.

Answer: D.
Senior Manager
Senior Manager
User avatar
P
Status: Whatever it takes!
Joined: 10 Oct 2018
Posts: 383
GPA: 4
Re: If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and  [#permalink]

Show Tags

New post 28 Mar 2019, 08:27
prekshita wrote:
Does this question even need any of the answer choices?

As in, this question can be answered without using either of the two options.

Is there any other question type where value of x needs to be calculated in series where the answer choices really are needed?




It is not possible. Without the statements, you CANNOT get a single solution. X can be anything! Statements are given either to find a solution or to prove something asked in the question.

P.S: By taking your statement into consideration, why would the test takers give such a question where the statements are useless? :lol:
_________________
Kudos OK Please!!

ALL ABOUT GMAT- \(https://exampal.com/gmat/blog/gmat-score-explained\)
Senior Manager
Senior Manager
User avatar
P
Status: Gathering chakra
Joined: 05 Feb 2018
Posts: 433
Premium Member
Re: If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and  [#permalink]

Show Tags

New post 10 Jun 2019, 11:46
Bunuel chetan2u I quickly recognized that only 9 will give an int answer (45/9=5) and satisfies the condition, and that there's only 1 number that gives us med = avg in that constraint.

But, is this a bad assumption since the prompt doesn't specify ints? What if in a different problem with a similar constraint the average and median were a non-int? We know that there's still only 1 correct value where med=avg, even if we don't calculate, right?
GMAT Club Bot
Re: If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and   [#permalink] 10 Jun 2019, 11:46
Display posts from previous: Sort by

If the average (arithmetic mean) of the five numbers x, 7, 2, 16 and

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  





Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne