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11 Oct 2021, 01:30
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
96% (01:19) correct
4%
(00:54)
wrong
based on 47
sessions
History
Date
Time
Result
Not Attempted Yet
If the circumference of the circle pictured above is \(16π\), what is the length of \(AC\)?
(A) \(4\sqrt{2}\)
(B) \(16\)
(C) \(16\sqrt{2}\)
(D) \(32\)
(E) \(16π\)
Attachment:
1.jpg [ 11.71 KiB | Viewed 1556 times ]
11 Oct 2021, 08:52
Kudos
Bookmarks
Correct option C = 16\(\sqrt{2}\)
Circumferrence given (2πr = 16π)
r= 8 D = 16
Diameter = Side of Square
By - Pythagoras Theorem
Diagonal of Sqaure AC =\(\sqrt{Side A^2+Side B^2}\)
Diagonal = \(\sqrt{16^2 + 16^2}\)
= 16 \(\sqrt{2}\)
= Option C
Circumferrence given (2πr = 16π)
r= 8 D = 16
Diameter = Side of Square
By - Pythagoras Theorem
Diagonal of Sqaure AC =\(\sqrt{Side A^2+Side B^2}\)
Diagonal = \(\sqrt{16^2 + 16^2}\)
= 16 \(\sqrt{2}\)
= Option C
11 Oct 2021, 09:31
Kudos
Bookmarks
Bunuel
\(2πr = 16π\)
So, \(r = 8\)
Now observe carfeully AC = Diagonal of the Square , where side of the square is \(8*2 = 16\)
Hence,Diagonal of the square will be \(16\sqrt{2}\), Answer must be (C)
