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If the figure above shows the diagonal of two rectangles, is the inner

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If the figure above shows the diagonal of two rectangles, is the inner  [#permalink]

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New post 13 Sep 2018, 04:11
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If the figure above shows the diagonal of two rectangles, is the inner rectangle a square?

(1) The outer rectangle is a square.
(2) The ratio of a side of the outer rectangle to its area is is x:x^2


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Re: If the figure above shows the diagonal of two rectangles, is the inner  [#permalink]

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New post 15 Sep 2018, 03:46
If the figure above shows the diagonal of two rectangles, is the inner rectangle a square?
The diagonals in a square are always 45 degrees, if we can prove the diagonal is at 45 degree we find the answer

(1) The outer rectangle is a square means the diagonal splits the square into two 45 45 90 triangle = a, a, a√2
Since the diagonal is 45 then the inner rectangle is also a square

(2) The ratio of a side of the outer rectangle to its area is is x:x^2

\(side:area = x:x^2\)

\(side/(side^2) = x:x^2\)

means the area is side times side which is not true for rectangle but true for square
sufficient

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Re: If the figure above shows the diagonal of two rectangles, is the inner &nbs [#permalink] 15 Sep 2018, 03:46
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If the figure above shows the diagonal of two rectangles, is the inner

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