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If the infinite sequence, M, is defined as M1 = 6, M2 = 96,

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If the infinite sequence, M, is defined as M1 = 6, M2 = 96, [#permalink]

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New post 09 Oct 2010, 23:02
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  45% (medium)

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69% (01:48) correct 31% (01:43) wrong based on 234 sessions

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If the infinite sequence, M, is defined as M1 = 6, M2 = 96, M3 = 996, … , Mk = 10^k – 4, is every term in this sequence divisible by q, if q is an even number?

(1) q is less than 45.

(2) At least 2 terms in the sequence are divisible by q.
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Re: If the infinite sequence, M, is defined as M1 = 6, M2 = 96, [#permalink]

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New post 10 Oct 2010, 00:02
mrinal2100 wrote:
If the infinite sequence, M, is defined as M1 = 6, M2 = 96, M3 = 996, … , Mk = 10k – 4, is every term in this sequence divisible by q, if q is an even number?

(1) q is less than 45.

(2) At least 2 terms in the sequence are divisible by q.


I think you mean to write that M_k = 10^k - 4, and not 10k - 4.

When I first read the question, I ask - what even number q would divide every term in the sequence? The only possibilities are 2 and 6, since these are the only even divisors of the first term of the sequence, which is 6. Each other term in the sequence is clearly divisible by 2, and since the digits of each term are multiples of 3, each term will also be divisible by 3, and thus by 6. So the question is really asking if we can determine that q is either 2 or 6.

Statement 1 then is clearly insufficient. From Statement 2, q is an even number which divides at least two terms in the sequence. Certainly q might be 2 or 6, but if you notice that each term in the sequence besides the first term ends in 96, you can see that each term in the sequence besides the first must be a multiple of 4. So q could also be equal to 4, and even combined the two Statements are not sufficient, and the answer is E.
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Re: If the infinite sequence, M, is defined as M1 = 6, M2 = 96, [#permalink]

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New post 14 Oct 2010, 03:27
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With (1) q is less than 45...q can be 2 which can divide each term Mk=(10^k)-4=(2* something) but it can be 8 also which cant divide 6 .It means it is not sufficient to answer.
With (2) ...Here also it can be 2 or 12 ...2 can divide all whereas 12 cant divide 6.

So both are not suffictent .Hence answer is E.

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Re: If the infinite sequence, M, is defined as M1 = 6, M2 = 96, [#permalink]

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New post 17 Feb 2011, 11:12
mrinal2100 wrote:
If the infinite sequence, M, is defined as M1 = 6, M2 = 96, M3 = 996, … , Mk = 10k – 4, is every term in this sequence divisible by q, if q is an even number?

(1) q is less than 45.

(2) At least 2 terms in the sequence are divisible by q.


Okay . This is how I solved it.

The series Mk=10^k=4 is always divisible by 2 and 3 .

(1) Both 2 and 3 are less than 45 - Insufficient
(2) More than 2 terms are divisible by 2 as well as by 3 - Insufficient

(1) +(2) => Again we get 2 and 3 - Hence, insufficient
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Re: If the infinite sequence, M, is defined as M1 = 6, M2 = 96, [#permalink]

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New post 09 Jan 2018, 19:43
maddy2u wrote:
mrinal2100 wrote:
If the infinite sequence, M, is defined as M1 = 6, M2 = 96, M3 = 996, … , Mk = 10k – 4, is every term in this sequence divisible by q, if q is an even number?

(1) q is less than 45.

(2) At least 2 terms in the sequence are divisible by q.


Okay . This is how I solved it.

The series Mk=10^k=4 is always divisible by 2 and 3 .

(1) Both 2 and 3 are less than 45 - Insufficient
(2) More than 2 terms are divisible by 2 as well as by 3 - Insufficient

(1) +(2) => Again we get 2 and 3 - Hence, insufficient


I know this is 6 years after the post, but just wanted to comment on this in case anyone else like myself is going through problems and comments.

Testing 3 is dangerous because the prompt says q is an even number. 2 and 4 would be better.
Re: If the infinite sequence, M, is defined as M1 = 6, M2 = 96,   [#permalink] 09 Jan 2018, 19:43
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