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If the least common multiple of the first 800 positive integers is n,
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04 Oct 2018, 15:18
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If the least common multiple of the first 800 positive integers is n, then what is the least common multiple of the first 801 positive integers in terms of n ? a. n b. 9n c. 89n d. 800n e. 801n
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Re: If the least common multiple of the first 800 positive integers is n,
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04 Oct 2018, 15:29
Turkish wrote: If the least common multiple of the first 800 positive integers is n, then what is the least common multiple of the first 801 positive integers in terms of n ?
a. n b. 9n c. 89n d. 800n e. 801n The least common multiple of the first 800 positive integers is nSo, n is a multiple of 1, a multiple of 2, a multiple of 3, a multiple of 4, . . . a multiple of 9, . . . ., a multiple of 89, . . . a multiple of 799, and a multiple of 800 What is the least common multiple of the first 801 positive integers in terms of n ?801 = ( 9)( 89) In other words, 801 is a multiple of 9, and 801 is a multiple of 89Since n is already a multiple of 9 and a multiple of 89, we know that n must be a multiple of 801 So, if n is the least common multiple of the first 800 positive integers, n is also the least common multiple of the first 801 positive integers. Answer: A Cheers, Brent
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Re: If the least common multiple of the first 800 positive integers is n,
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11 Dec 2018, 06:34
GMATPrepNow wrote: Turkish wrote: If the least common multiple of the first 800 positive integers is n, then what is the least common multiple of the first 801 positive integers in terms of n ?
a. n b. 9n c. 89n d. 800n e. 801n The least common multiple of the first 800 positive integers is nSo, n is a multiple of 1, a multiple of 2, a multiple of 3, a multiple of 4, . . . a multiple of 9, . . . ., a multiple of 89, . . . a multiple of 799, and a multiple of 800 What is the least common multiple of the first 801 positive integers in terms of n ?801 = ( 9)( 89) In other words, 801 is a multiple of 9, and 801 is a multiple of 89Since n is already a multiple of 9 and a multiple of 89, we know that n must be a multiple of 801 So, if n is the least common multiple of the first 800 positive integers, n is also the least common multiple of the first 801 positive integers. Answer: A Cheers, Brent Hi Brent, I solved it as follows. Please correct me if I am wrong. I assumed the numbers to be 1,2,3,4,5. LCM is 60 LCM of 1,2,3,4,5,6 is also 60. Hence A.



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Re: If the least common multiple of the first 800 positive integers is n,
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11 Dec 2018, 08:33
Kezia9 wrote: GMATPrepNow wrote: Turkish wrote: If the least common multiple of the first 800 positive integers is n, then what is the least common multiple of the first 801 positive integers in terms of n ?
a. n b. 9n c. 89n d. 800n e. 801n The least common multiple of the first 800 positive integers is nSo, n is a multiple of 1, a multiple of 2, a multiple of 3, a multiple of 4, . . . a multiple of 9, . . . ., a multiple of 89, . . . a multiple of 799, and a multiple of 800 What is the least common multiple of the first 801 positive integers in terms of n ?801 = ( 9)( 89) In other words, 801 is a multiple of 9, and 801 is a multiple of 89Since n is already a multiple of 9 and a multiple of 89, we know that n must be a multiple of 801 So, if n is the least common multiple of the first 800 positive integers, n is also the least common multiple of the first 801 positive integers. Answer: A Cheers, Brent Hi Brent, I solved it as follows. Please correct me if I am wrong. I assumed the numbers to be 1,2,3,4,5. LCM is 60 LCM of 1,2,3,4,5,6 is also 60. Hence A. It's a useful strategy to examine a smaller case (first 5 positive integers vs the first 800 positive integers), but it happens to be a lucky coincidence that you found the correct answer. For example, if you had examined the first 4 positive integers, you would have gotten a different answer. If the numbers are 1, 2, 3, 4, then the LCM = 12 But the LCM of 1, 2, 3, 4, and 5 is not 12 (it's 60) Cheers, Brent
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Re: If the least common multiple of the first 800 positive integers is n,
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