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# If the length of a diagonal of a square is 2x^(1/2), what is the area

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Re: If the length of a diagonal of a square is 2x^(1/2), what is the area [#permalink]
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parkhydel
If the length of a diagonal of a square is $$2\sqrt{x}$$, what is the area of the square in terms of x ?

A. $$\sqrt{x}$$

B. $$\sqrt{2x}$$

C. $$2\sqrt{x}$$

D. x

E. 2x

PS60231.02

Well, if we know the relation between the diagonal and the side of a square. The problem becomes fairly simple.

Let us assume that the side of the square is 's'. The relation between the side of a square and its diagonal (d) is 'd= s $$\sqrt{2}$$

Hence,

s $$\sqrt{2}$$= 2 $$\sqrt{x}$$
(These two are equal since we are talking about the length of the same diagonal)

s = $$2 \sqrt{x}$$ / $$\sqrt{2}$$

Squaring both the sides (since area of a square is ($$S^2$$)

$$S^2$$ = $$\frac{4x}{2}$$

$$S^2$$ = 2x (Area of Square)

Hope this helps a little
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Re: If the length of a diagonal of a square is 2x^(1/2), what is the area [#permalink]
given that digonal of square = 2√x
we know that digonal of square = √2 * side of square
so from given info ; side of square = 2√x/2 ; √2x
area of square ( √2x) ^2 ; 2x
OPTION E

parkhydel
If the length of a diagonal of a square is $$2\sqrt{x}$$, what is the area of the square in terms of x ?

A. $$\sqrt{x}$$

B. $$\sqrt{2x}$$

C. $$2\sqrt{x}$$

D. x

E. 2x

PS60231.02
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Re: If the length of a diagonal of a square is 2x^(1/2), what is the area [#permalink]
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Since it's a square we get an isoceles right triangle with the diagonal and the sides will be in the ratio
1:1:√2
?:?:2√x
So side of the square is2√x/√2
Square this for Area 4x/2=2x
Hence E

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If the length of a diagonal of a square is 2x^(1/2), what is the area [#permalink]
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parkhydel
If the length of a diagonal of a square is $$2\sqrt{x}$$, what is the area of the square in terms of x ?

A. $$\sqrt{x}$$

B. $$\sqrt{2x}$$

C. $$2\sqrt{x}$$

D. x

E. 2x

PS60231.02

Solution:

For a square, diagonal = side√2, so we have:

2√x= side√2

2√(x/2) = side

Thus, the area of the square is [2√(x/2)]^2 = 4(x/2) = 2x.

Alternate Solution:

The area of a square with diagonal length of d is A = d^2/2. Thus, the area of the square in question is (2√x)^2 / 2 = (4x)/2 = 2x.

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Re: If the length of a diagonal of a square is 2x^(1/2), what is the area [#permalink]
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The area of a square when diagonal is give = $$\frac{1}{2}$$$$d^{2}$$

So the area now will be $$\frac{1}{2}*(2\sqrt{x})^{2}$$

= $$\frac{1}{2}$$ * 4x

= 2x
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Re: If the length of a diagonal of a square is 2x^(1/2), what is the area [#permalink]
2 ways to approach this que.
1.with direct formula
Area = 1/2 (diagonal)^2

2.as pee info it is square and diagonal will cut right angle to 45:45.
So using 45:45:90 we can find side of square
Area= side^2

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Re: If the length of a diagonal of a square is 2x^(1/2), what is the area [#permalink]

Solution

Given
• Length of a diagonal of a square = $$2 \sqrt{(x)}$$.

To Find
• Area of square in terms of x.

Approach and Working out
Let’s say that the square has all of its sides = a units. Area of the square will be $$a^2$$.
• Diagonal of the square can be found out using Pythagoras theorem since all the angles of the square are of 90 degrees each.
o Therefore $$a^2 + a^2 = diagonal ^2$$
o Therefore $$diagonal = \sqrt{(2a^2)}$$
.
Now, diagonal of the square $$= 2\sqrt{(x)} = \sqrt{(2a^2)}$$.
• Finding the side of the square (a) in terms of ‘x’: $$2a^2 = 4x$$.
o $$a^2 = 2x$$. Therefore $$a = \sqrt{(2x)}$$.

Area of a square $$= a^2 = (\sqrt{(2x)})^2 = 2x$$.

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If the length of a diagonal of a square is 2x^(1/2), what is the area [#permalink]
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Solution:

Area of a square with diagonal length of d= d^2/2

d = 2√x

=>Area = (2√x)^2/2

=2x (option e)

Hope this helps

Devmitra Sen (GMAT Quant Expert)
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Re: If the length of a diagonal of a square is 2x^(1/2), what is the area [#permalink]
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parkhydel
If the length of a diagonal of a square is $$2\sqrt{x}$$, what is the area of the square in terms of x ?

A. $$\sqrt{x}$$

B. $$\sqrt{2x}$$

C. $$2\sqrt{x}$$

D. x

E. 2x

PS60231.02

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Re: If the length of a diagonal of a square is 2x^(1/2), what is the area [#permalink]
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