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If the lengths of the sides of squares S and T are √5 and √7 resepecti

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If the lengths of the sides of squares S and T are √5 and √7 resepecti [#permalink]

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New post 03 Oct 2017, 05:43
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Difficulty:

  25% (medium)

Question Stats:

97% (00:13) correct 3% (00:27) wrong based on 29 sessions

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If the lengths of the sides of squares S and T are √5 and √7 resepectively, then the area of T minus the area of S is

(A) √2
(B) 2
(C) 4
(D) 24
(E) 35
[Reveal] Spoiler: OA

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Re: If the lengths of the sides of squares S and T are √5 and √7 resepecti [#permalink]

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New post 03 Oct 2017, 06:44
the area of T- S = (T^2 -S^2)
T^2 = (√7 )^2 = 7 and S^2 = (√5)^2 = 5
therefore; 7-5 = 2
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Re: If the lengths of the sides of squares S and T are √5 and √7 resepecti [#permalink]

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New post 05 Oct 2017, 10:08
Bunuel wrote:
If the lengths of the sides of squares S and T are √5 and √7 resepectively, then the area of T minus the area of S is

(A) √2
(B) 2
(C) 4
(D) 24
(E) 35


The area of a square is s^2, where s is the length of the side. Thus, the area of square T is (√7)^2 = 7, and the area of square S is (√5)^2 = 5. Thus, the difference of the two areas is 7 - 5 = 2.

Answer: B
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Re: If the lengths of the sides of squares S and T are √5 and √7 resepecti   [#permalink] 05 Oct 2017, 10:08
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If the lengths of the sides of squares S and T are √5 and √7 resepecti

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