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If the number of cars in city X this year is 520,800 which is 24% more

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If the number of cars in city X this year is 520,800 which is 24% more  [#permalink]

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New post 23 Jan 2017, 04:33
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Question Stats:

81% (01:54) correct 19% (02:01) wrong based on 102 sessions

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If the number of cars in city X this year is 520,800 which is 24% more than there were in city X last year, how many cars were there in city X last year?

A. 395,808
B. 420,000
C. 447,888
D. 496,800
E. 645,795

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Re: If the number of cars in city X this year is 520,800 which is 24% more  [#permalink]

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New post 23 Jan 2017, 05:01
Bunuel wrote:
If the number of cars in city X this year is 520,800 which is 24% more than there were in city X last year, how many cars were there in city X last year?

A. 395,808
B. 420,000
C. 447,888
D. 496,800
E. 645,795


lets X = original number of cars
24% more than X can be written as
1.24*X = 520800
X = 420000

Hence option B is correct
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Re: If the number of cars in city X this year is 520,800 which is 24% more  [#permalink]

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New post 25 Jan 2017, 11:18
Bunuel wrote:
If the number of cars in city X this year is 520,800 which is 24% more than there were in city X last year, how many cars were there in city X last year?

A. 395,808
B. 420,000
C. 447,888
D. 496,800
E. 645,795


We are given that the number of cars in city X this year is 520,800, which is 24% more than there were in city X last year. If we let the number of cars in city X last year = c, we can create the following equation:

520,800 = 1.24c

c = 420,000

Answer: B
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Re: If the number of cars in city X this year is 520,800 which is 24% more  [#permalink]

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New post 12 Mar 2017, 08:13
520 800=1,24*last year
last year is 520800/1,24=420000
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Re: If the number of cars in city X this year is 520,800 which is 24% more  [#permalink]

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New post 12 Mar 2017, 12:21
Bunuel wrote:
If the number of cars in city X this year is 520,800 which is 24% more than there were in city X last year, how many cars were there in city X last year?

A. 395,808
B. 420,000
C. 447,888
D. 496,800
E. 645,795


\(\frac{520800}{124}*100\)

\(= 420,000\)

Thus, answer must be ( B ) 420,000
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Re: If the number of cars in city X this year is 520,800 which is 24% more  [#permalink]

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New post 29 Nov 2017, 21:44
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Hi All,

We're told that the number of cars in city X this year is 520,800 and that total is 24% more than there were in city X last year. We're asked for the number of cars that were there in city X last year. While the numbers in this prompt are not 'pretty', the answer choices are 'spaced out' enough that we can do a bit of estimation and some 'brute force' math to get to the answer.

To start, 24% of 100,000 = 24,000 (so a 24% increase would be 124,000 total cars). Thus, we can quickly map out increases of 100,000 cars...
200,000 + 48,000 = 248,000
300,000 + 72,000 = 372, 000
400,000 + 96,000 = 496,000
500,000 + 120,000 = 620,000

Since 520,800 is far closer to 496,000 than it is to 620,000, the total number of cars last year would be a bit more than 400,000. There's only one answer that matches...

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Re: If the number of cars in city X this year is 520,800 which is 24% more  [#permalink]

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New post 29 Nov 2017, 22:41
Bunuel wrote:
If the number of cars in city X this year is 520,800 which is 24% more than there were in city X last year, how many cars were there in city X last year?

A. 395,808
B. 420,000
C. 447,888
D. 496,800
E. 645,795


Number of cars in City X this year = 520,800
It is 24% more than there were in City X last year.
So 520800 = 1.24 * cars last year
Cars last year = 520,800/ 1.24 = 420,000

Answer B
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Re: If the number of cars in city X this year is 520,800 which is 24% more &nbs [#permalink] 29 Nov 2017, 22:41
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