gauravsoni
If the point (4,6) lies on line l, and the point (x,3) also lies on line l, what is the value of x?
(1) l passes through (0,0).
(2) The slope of line l is positive.
Can someone please explain how to approach such a problem.
Hello Guarav Soni,
We are given that pts (4,6 ) and (x,3) lie on Line L. We need to find x
St 1 tells us that pt(0,0) is also on the line so we can form an equation using the following
\((y-y1)= m(x-x1)\) where \(Slope, m = (y2-y1)/(x2-x1)\)
Since we know that pt (0,0) and (4,6) are on line we can find m = (6-0)/(4-0) or 3/2
Therefore (y-0)= 3/2 (x-0) or\(y=3x/2\)This is the equation of the line
Subsitute y=3 in this equation and you get x= 2
So St 1 is sufficient and option B,C and E can be ruled out here
St 2 tells us that the slope of the line is positive. A positive slope line means it pass through quadrant I and III and there can be multiple values
So St 2 is insufficient.D ruled out
Ans is A
You should brush your knowledge on the subject. A good source will be Gmatclub Math Book. More on this topic can be found here :
math-coordinate-geometry-87652.htmlgmat-math-book-in-downloadable-pdf-format-130609.htmlgood explanation, i do have to brush up the coordinate geometry, really weak at it.