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If the population of city A is increased by A% in year 2006

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If the population of city A is increased by A% in year 2006  [#permalink]

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New post 04 Apr 2012, 08:50
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73% (01:57) correct 27% (02:42) wrong based on 465 sessions

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If the population of city A is increased by A% in year 2006 from year 2005 and b% in 2007 from year 2006. If a+b=20, then what is the maximum percentage increase in population of city A from 2005 to year 2007?

A. 20.19%
B. 20.36%
C. 20.51%
D. 20.84%
E. 21%
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Re: If the population of city A is increased by A% in year 2006  [#permalink]

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New post 04 Apr 2012, 09:17
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LM wrote:
If the population of city A is increased by A% in year 2006 from year 2005 and b% in 2007 from year 2006. If a+b=20, then what is the maximum percentage increase in population of city A from 2005 to year 2007?

A. 20.19%
B. 20.36%
C. 20.51%
D. 20.84%
E. 21%


Say the population of the city was 100 in 2005, then in 2007 it would be \(100(1+\frac{a}{100})(1+\frac{b}{100})=\frac{ab}{100}+a+b+100=\frac{ab}{100}+120\) (since \(a+b=20\)).

So, in order to maximize this expression we need to maximize the value of \(ab\), when given that \(a+b=20\). Useful property: for given sum of two numbers, their product is maximized when they are equal. Hence, \(ab\) will be maximized for \(a=b=10\) --> \(120+\frac{ab}{100}=120+1=121\).

Answer: E.
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Re: If the population of city A is increased by A% in year 2006  [#permalink]

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New post 14 Jun 2013, 05:27
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Re: If the population of city A is increased by A% in year 2006  [#permalink]

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New post 30 Aug 2014, 02:58
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\(2005 ------2006-------------2007\)
\(x --------x(1+\frac{a}{100})----------x(1+\frac{a}{100})(1+\frac{b}{100})\)

\(% increase=\frac{x(1+\frac{a}{100})(1+\frac{b}{100})-x}{x}*100\)

\(=\frac{(100+a)(100+b)-100^2}{100^2}*100\)

\(=\frac{a+b+ab}{100}\)
as given a+b=20
\(=20+\frac{ab}{100}\)

To maximize \(\frac{ab}{100}\) we must keep a=b=10.

i.e. %increase = 20 + 1=21 (E)
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Re: If the population of city A is increased by A% in year 2006  [#permalink]

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New post 09 Aug 2017, 15:59
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Here is what I did on this one ->
I did not solve it to maximise but rather used hit and trial.
Let the population in 2005 be 100.
Since in most GMAT questions symmetry works perfectly what if a=b=10

Then 100 => 110 => 121

Hence 21% gain is possible.

Scanning the options => 21 is the highest possible value.

Hence E.

But I like what Bunuel did here.

To maximise ab given the sum a+b we must make a=b.


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Re: If the population of city A is increased by A% in year 2006  [#permalink]

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New post 05 Oct 2019, 20:51
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Re: If the population of city A is increased by A% in year 2006   [#permalink] 05 Oct 2019, 20:51
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