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555-605 Level|   Arithmetic|      
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Bunuel
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If the terms of a series are either "2" or "24" and the sum of all the 19 Aug 2015, 22:55
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If the terms of a series are either "2" or "24" and the sum of all the terms of the series is 124, then which of the following could be the number of "2s" in the series?

A. 26
B. 29
C. 35
D. 40
E. 48

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A
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If the terms of a series are either "2" or "24" and the sum of all the 19 Aug 2015, 23:07
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Bunuel
If the terms of a series are either "2" or "24" and the sum of all the terms of the series is 124, then which of the following could be the number of "2s" in the series?

A. 26
B. 29
C. 35
D. 40
E. 48

Ans: A

Solution: we are not certain how many 2 or 24 are there. but as given sum of all the terms is 124 means 24*5= 120 so number of 24 can't be more than 5
so 24x +2y = 124
now y is possible numbers of 2 sequence can have.
24*5 + 2y =124 then y=2
24*4 + 2y = 124 then y=14
24*3 +2y = 124 then y= 26
24*2 +2y =124 then y = 38
24 +2y = 124 then y= 50
26 is the ans.
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If the terms of a series are either "2" or "24" and the sum of all the 19 Aug 2015, 23:08
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Eq is 2X+24Y=124

We need to find possible values of X. we can put values of X and check...

2(26)+24Y=52+24Y; Y can be 3; 'possible'
2(29)+24Y=58+24Y; 'not possible'
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All other values of X not possible if we check with our equation.
So Ans is 'A'
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If the terms of a series are either "2" or "24" and the sum of all the 19 Aug 2015, 23:47
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If the terms of a series are either "2" or "24" and the sum of all the terms of the series is 124, then which of the following could be the number of "2s" in the series?

Let us consider we have only 2s in the series, then we have 62 "2s" in total.(62 is not there in the options)

To include a 24 in the series we have to take out 12 "2s".
Including one 24 in the series, we have = 62-12 = 50 "2s" (50 is not there in the options)
Including two 24s in the series, we have = 62-12-12 = 38 "2s" (38 is not there in the options)
Including three 24s in the series, we have = 62-12-12-12 = 26 "2s" (26 is there in the options)

Ans:A
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If the terms of a series are either "2" or "24" and the sum of all the 20 Aug 2015, 08:27
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Possible number of "2s" in the series?
2x+24y=124
Find x
testing out the choices, only 26×2 + 24×3 =124

Answer: A. 26
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If the terms of a series are either "2" or "24" and the sum of all the 21 Aug 2015, 06:28
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Bunuel
If the terms of a series are either "2" or "24" and the sum of all the terms of the series is 124, then which of the following could be the number of "2s" in the series?

A. 26
B. 29
C. 35
D. 40
E. 48

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Using the given options,
If no of 2's are 29, then sum of 2's=58 and sum of 24's left=124-58=66 which is not possible
If no of 2's=35, then sum of 2's =70 and sum of 24's left=124-70=54 which is not possible
If no of 2's=26, then sum of 2's=52 and sum of 24's left=124-52=72 which is divisible by 24
Answer A
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If the terms of a series are either "2" or "24" and the sum of all the 21 Aug 2015, 12:24
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substituted the value as 2..gives 2*26 =52 --> which leaves us with 72.. which in turn is divisible by 24
so :A
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If the terms of a series are either "2" or "24" and the sum of all the 21 Aug 2015, 15:05
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Bunuel
If the terms of a series are either "2" or "24" and the sum of all the terms of the series is 124, then which of the following could be the number of "2s" in the series?

A. 26
B. 29
C. 35
D. 40
E. 48

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Testing of the options is the easiest in my opinion

A - 26*2 = 52, 124-52 = 72 --> divisible by 24
B,C,D,E leave values of 46, 54, 44, and 28 respectively which are not divisible by 24

So answer is A.
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If the terms of a series are either "2" or "24" and the sum of all the 10 Mar 2017, 10:26
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Bunuel
If the terms of a series are either "2" or "24" and the sum of all the terms of the series is 124, then which of the following could be the number of "2s" in the series?

A. 26
B. 29
C. 35
D. 40
E. 48

We can create the following equation in which a = the number of 2s and b = the number of 24s:

2a + 24b = 124

a + 12b = 62

12b = 62 - a

b = (62 - a)/12

Since 62 - a must be a multiple of 12, a could be 2, 14, 26, 38, or 50. Of the answer choices, 26 is the only value listed.

Answer: A
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If the terms of a series are either "2" or "24" and the sum of all the 18 Mar 2017, 20:38
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2x + 24 y = 124
2(x+12y) = 124
x + 12y = 62

Now let's do process elimination

If x is 26, then
26 + 12 y = 62
12 y = 62 - 26
y = 3

If you try the other answers, you would realize that those numbers will not result an integer.
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If the terms of a series are either "2" or "24" and the sum of all the 18 Jun 2018, 16:13
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The MAX number of "24" that can be in the series is 5, since 24*5 = 120, and thus the number of "2" would then be 2, since 2*2 = 4, and further 120 + 4 = 124. BUT 2 is not one of the options so that can't be correct.

Lets try 3 "24".
24 * 3 = 72.
124 - 72 = 52
52 / 2 = 26 ---> This is the number of "2" that can be in a series with 3 "24"

26 is option A, thus we have our answer.
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