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04 Jan 2013, 04:37
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E
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Difficulty:
75%
(hard)
Question Stats:
54% (02:16) correct
46%
(02:23)
wrong
based on 211
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If these lines intersect at point C, is either m or p greater than 0?
Line a is defined by the equation y = mx + 4.
Line b is defined the the equation y = px - 2.
(1) The x intercept of line b < 0.
(2) |m| > |p|
Line a is defined by the equation y = mx + 4.
Line b is defined the the equation y = px - 2.
(1) The x intercept of line b < 0.
(2) |m| > |p|
04 Jan 2013, 04:58
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mridulparashar1
1) x intercept of b is = \(\frac{2}{p}\). Hence we get that p is negative. We still do not have any information about m. Insufficient.
2) No useful info. We need the polarity of m and p. Modulus does not give either. Insufficient.
1 & 2 together, we still do not know whether m is positive or negative. Insufficient.
Answer is hence E.
04 Jan 2013, 05:00
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If these lines intersect at point C, is either m or p greater than 0?
Line a is defined by the equation y = mx + 4.
Line b is defined the the equation y = px - 2.
(1) The x intercept of line b < 0. The x-intercept is the value of x for y=0, thus we are given that 2/p<0, which implies that p<0. So, p is not greater than 0. But we know nothing about m. Not sufficient.
(2) | m | > | p |. Clearly insufficient.
(1)+(2) Still m can be positive as well as negative. For example, m=2 and p=-1 (|m|>|p|) OR m=-2 and p=-1 (|m|>|p|). Not sufficient.
Answer: E.
Line a is defined by the equation y = mx + 4.
Line b is defined the the equation y = px - 2.
(1) The x intercept of line b < 0. The x-intercept is the value of x for y=0, thus we are given that 2/p<0, which implies that p<0. So, p is not greater than 0. But we know nothing about m. Not sufficient.
(2) | m | > | p |. Clearly insufficient.
(1)+(2) Still m can be positive as well as negative. For example, m=2 and p=-1 (|m|>|p|) OR m=-2 and p=-1 (|m|>|p|). Not sufficient.
Answer: E.
