Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
Learn the winning strategy for a high GRE score — what do people who reach a high score do differently? We're going to share insights, tips and strategies from data we've collected from over 50,000 students who used examPAL.
Aiming to score 760+? Attend this FREE session to learn how to Define your GMAT Strategy, Create your Study Plan and Master the Core Skills to excel on the GMAT.
Re: If w, x and y are integers such that w < x < y, are w, x and
[#permalink]
Show Tags
12 Nov 2013, 13:11
2
If w, x and y are integers such that w < x < y, are w, x and y consecutive integers?
(1) y - w = 2 --> y = w + 2. Thus we have that w < x < (w + 2). There is only one integer between w and w + 2, which is w + 1. Thus the three integers are w, x = w + 1, and y = w + 2 --> w, x and y are constitutive integers. Sufficient.
(2) The average (arithmetic mean) of w, x and y is x. If w=0, x=5 and y=10, then the answer is NO but if w=0, x=1 and y=2, then the answer is YES. Not sufficient.
If w, x and y are integers such that w < x < y, are w, x and
[#permalink]
Show Tags
09 Apr 2018, 10:48
Bunuel wrote:
If w, x and y are integers such that w < x < y, are w, x and y consecutive integers?
(1) y - w = 2 --> y = w + 2. Thus we have that w < x < (w + 2). There is only one integer between w and w + 2, which is w + 1. Thus the three integers are w, x = w + 1, and y = w + 2 --> w, x and y are constitutive integers. Sufficient.
(2) The average (arithmetic mean) of w, x and y is x. If w=0, x=5 and y=10, then the answer is NO but if w=0, x=1 and y=2, then the answer is YES. Not sufficient.
I understand the no. approach for St.2, but I don't understand what I am doing wrong.
I assumed that the nos. are consecutive. Let w=n, so x=n+1 and y=n+2 The avg of three no. would be [n+n+1+n+2]/[3]= n+1, which is equal to x, same as St.2, so the assumption is correct.
Re: If w, x and y are integers such that w < x < y, are w, x and
[#permalink]
Show Tags
09 Apr 2018, 12:12
ShashwatPrakash wrote:
Bunuel wrote:
If w, x and y are integers such that w < x < y, are w, x and y consecutive integers?
(1) y - w = 2 --> y = w + 2. Thus we have that w < x < (w + 2). There is only one integer between w and w + 2, which is w + 1. Thus the three integers are w, x = w + 1, and y = w + 2 --> w, x and y are constitutive integers. Sufficient.
(2) The average (arithmetic mean) of w, x and y is x. If w=0, x=5 and y=10, then the answer is NO but if w=0, x=1 and y=2, then the answer is YES. Not sufficient.
I understand the no. approach for St.2, but I don't understand what I am doing wrong.
I assumed that the nos. are consecutive. Let w=n, so x=n+1 and y=n+2 The avg of three no. would be [n+n+1+n+2]/[3]= n+1, which is equal to x, same as St.2, so the assumption is correct.
Kindly explain.
You sowed that (2) is true for consecutive integers but what if (2) is also true if the integers are not consecutive? In this case you'd get an YES and a NO answer to the question.
_________________
close
54% (01:16) correct 
