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If when x is divided by z, the result is y remainder q, then which of

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If when x is divided by z, the result is y remainder q, then which of  [#permalink]

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New post 31 Oct 2018, 01:00
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A
B
C
D
E

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Re: If when x is divided by z, the result is y remainder q, then which of  [#permalink]

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New post 31 Oct 2018, 01:08
\(Dividend = Divisor*Quotient + Remainder\).

\(x = z*y + q\)
divide by z
\(\frac{x}{z} = y + \frac{q}{z}\)

moving y to LHS gives

\(\frac{x}{z} - y = \frac{q}{z}\)

B is the answer.
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Re: If when x is divided by z, the result is y remainder q, then which of  [#permalink]

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New post 13 Mar 2019, 09:37
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Bunuel wrote:
If when x is divided by z, the result is y remainder q, then which of the following must be true?


A. \(z(y + q) = x\)

B. \(\frac{x}{z}-y=\frac{q}{z}\)

C. \(xz - q = y\)

D. \(\frac{x}{z}=y+q\)

E. \(\frac{x}{z}=yz+q\)


When it comes to remainders, there's a nice rule that says, "If N divided by D equals Q with remainder R, then N = DQ + R"
For example, since 17 divided by 5 equals 3 with remainder 2, then we can write 17 = (5)(3) + 2
Likewise, since 53 divided by 10 equals 5 with remainder 3, then we can write 53 = (10)(5) + 3

GIVEN: when x is divided by z, the result (aka quotient) is y remainder is q
Applying the above rule, we get: x = zy + q .
Check the answer choices . . . x = zy + q is not there.
Looks like we need to rewrite the expression

Take: x = zy + q
Subtract yz from both sides to get: x - zy = q
Divide both sides by z to get: x/z - zy/z = q/z
Simplify to get: x/z - y = q/z

Answer: B

Cheers,
Brent

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Re: If when x is divided by z, the result is y remainder q, then which of  [#permalink]

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New post 15 Mar 2019, 06:40
Bunuel wrote:
If when x is divided by z, the result is y remainder q, then which of the following must be true?


A. \(z(y + q) = x\)

B. \(\frac{x}{z}-y=\frac{q}{z}\)

C. \(xz - q = y\)

D. \(\frac{x}{z}=y+q\)

E. \(\frac{x}{z}=yz+q\)


We can create the equation:

x/z = y + q/z

x/z - y = q/z

Answer: B
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Re: If when x is divided by z, the result is y remainder q, then which of   [#permalink] 15 Mar 2019, 06:40
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