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Given, \(x<0\) and \(0<y<|x|\)

so, \(y^2 < x^2\) [squaring the 2nd inequality on both sides, since both sides of the inequality is +ve]

\(y^2 - x^2 < 0\)

Ans A IMO
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Concept: We can SQUARE or Raise to an EVEN Exponent Both Sides of an Inequality if we know both sides are within (+)Positive Value Ranges ---- and we do NOT have to Reverse the Inequality Sign


X < 0 ----- X = (-)Negative Value


0 < Y < [X] ----- Both Y and the OUTPUT of Absolute Value of [X] will be (+)Positive

--SQUARING All Sides of the Inequality ----


(0)^2 < (Y)^2 < (X)^2


---Subtracting (X)^2-----

0 < (Y)^2 - (X)^2 < 0


-A-
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Square of number cannot be less than 0, hence C,D,E can be negated.

To check between A and B,

Since we can write |x| as \(\sqrt{x^2}\).

Hence \(\sqrt{x^2}\) > y.

Squaring both sides we get: \(x^2 > y^2\).

Subtracting \(y^2\) from both sides we get \(x^2 - y^2 > 0\).
Multiplying both sides by -1 we get:

\(y^2-x^2 > 0\)

Hence A is the correct answer.
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