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# If x ≠ 0, what is the value of (x^p/x^q)^3 ? (1) p - q = 1 (2) x = 4

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Math Expert
Joined: 02 Sep 2009
Posts: 44623
If x ≠ 0, what is the value of (x^p/x^q)^3 ? (1) p - q = 1 (2) x = 4 [#permalink]

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16 Dec 2017, 01:51
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Question Stats:

74% (00:33) correct 26% (00:12) wrong based on 39 sessions

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If x ≠ 0, what is the value of $$(\frac{x^p}{x^q})^3$$ ?

(1) p - q = 1
(2) x = 4
[Reveal] Spoiler: OA

_________________
Math Expert
Joined: 02 Sep 2009
Posts: 44623
Re: If x ≠ 0, what is the value of (x^p/x^q)^3 ? (1) p - q = 1 (2) x = 4 [#permalink]

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16 Dec 2017, 01:53
Bunuel wrote:
If x ≠ 0, what is the value of $$(\frac{x^p}{x^q})^3$$ ?

(1) p - q = 1
(2) x = 4

Similar question from OG: https://gmatclub.com/forum/if-x-0-what- ... 66516.html
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Joined: 24 Nov 2016
Posts: 148
Re: If x ≠ 0, what is the value of (x^p/x^q)^3 ? (1) p - q = 1 (2) x = 4 [#permalink]

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16 Dec 2017, 09:18
Bunuel wrote:
If x ≠ 0, what is the value of $$(\frac{x^p}{x^q})^3$$ ?

(1) p - q = 1
(2) x = 4

Simplify: $$(\frac{x^p}{x^q})^3 =x^{3(p-q)}$$

(1) p - q = 1. Nothing about x, insufficient.

(2) x = 4. Nothing about p-q, insufficient.

Combining both (1) and (2) we have: $$x^{3(p-q)}=(4)^{3(1)}=64,$$ sufficient.

Re: If x ≠ 0, what is the value of (x^p/x^q)^3 ? (1) p - q = 1 (2) x = 4   [#permalink] 16 Dec 2017, 09:18
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