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Bunuel
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Bunuel
If x ≠ 0, \(\frac{x*(x^5)^2}{x^4} =\)

(A) x^5
(B) x^6
(C) x^7
(D) x^8
(E) x^9


solve \(\frac{x*(x^5)^2}{x^4} =\)
we get x^11/x^4 = x^7
IMO C
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\(\frac{x(x^5)^2}{x^4} = \frac{x(x^10)}{x^4} = x*x^6 = x^7\)

Option C
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Bunuel
If x ≠ 0, \(\frac{x*(x^5)^2}{x^4} =\)

(A) x^5
(B) x^6
(C) x^7
(D) x^8
(E) x^9

x^11/x^4 => X^(11-4) => X^7
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