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If x ≠ 0, x(x^5)^2/x^4 = ?

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Bunuel
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If x ≠ 0, x*(x^5)^2/x^4 = [#permalink] New post  10 Apr 2019, 00:58
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If x ≠ 0, \(\frac{x*(x^5)^2}{x^4} =\)

(A) x^5
(B) x^6
(C) x^7
(D) x^8
(E) x^9
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BrentGMATPrepNow
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Re: If x ≠ 0, x(x^5)^2/x^4 = ? [#permalink] New post  09 Sep 2021, 07:59
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Bunuel wrote:
If \(x ≠ 0, \frac{x(x^5)^2}{x^4} = ?\)

(A) \(x^5\)

(B) \(x^6\)

(C) \(x^7\)

(D) \(x^8\)

(E) \(x^9\)


\(\frac{x(x^5)^2}{x^4} =\frac{x(x^{10})}{x^4}\) after applying the Power of a Power rule

\( =\frac{x^{11}}{x^4}\) after applying the Product rule

\( =x^7\) after applying the Quotient rule

Answer: C

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Re: If x ≠ 0, x*(x^5)^2/x^4 = [#permalink] New post  10 Apr 2019, 01:07
Bunuel wrote:
If x ≠ 0, \(\frac{x*(x^5)^2}{x^4} =\)

(A) x^5
(B) x^6
(C) x^7
(D) x^8
(E) x^9


Given,

\(x(x^5)^2 / x^4\)

\(x * x^{10} / x^4\)

\(x^{11}/ x^4\)

\(x^{11 - 4}\)

\(x^7\)

C is the correct answer.
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Re: If x ≠ 0, x*(x^5)^2/x^4 = [#permalink] New post  10 Apr 2019, 02:58
Bunuel wrote:
If x ≠ 0, \(\frac{x*(x^5)^2}{x^4} =\)

(A) x^5
(B) x^6
(C) x^7
(D) x^8
(E) x^9



solve \(\frac{x*(x^5)^2}{x^4} =\)
we get x^11/x^4 = x^7
IMO C
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sj296
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Re: If x ≠ 0, x(x^5)^2/x^4 = [#permalink] New post  02 Sep 2021, 10:40
\(\frac{x(x^5)^2}{x^4} = \frac{x(x^10)}{x^4} = x*x^6 = x^7\)

Option C
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Re: If x ≠ 0, x(x^5)^2/x^4 = [#permalink]
02 Sep 2021, 10:40
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