Lets get down to statements directly.
1) \(x^x < 0\)
For \(x^x\) to be negative, x needs to satisfy two conditions: a) x needs to be negative and b) x needs to odd so that negative sign of x remains the same.
With these constraints, lets take some values to check sufficiency.
If x=-1. (Note here, x is given not equal to 1, but it can most certainly be -1)
Thus, \(\frac{|x| - 1}{x - 1}\)=0
If x=-3Thus, \(\frac{|x| - 1}{x - 1}\)=-1/2
Clearly, we cannot arrive at a unique value of the expression.
Hence, insufficient2) \(\frac{|x|}{x}=-1\)
Here, x can take any negative value because the numerator will always be positive (due to mod) and denominator will continue to be negative value. Note here that x doesn't have to be -1 here because the common number in numerator and denominator is essentially cancelling each other and giving us 1 any way.
Now, we can use the same example from statement 1 here (x=-1 and x=-3) and declare that this condition is
also insufficientCombining 1) & 2), we can clearly see that statement 2 is not adding any new information to statement 1 and therefore not changing our result of insufficiency.
Hence, answer is E