jorgetomas9
GMATinsight
AnisMURR
If \(x^3 < x^2\), is \(x < 0\) ?
A) \(|x| > x^2\)
B) \(x > x^2\)
Given: \(x^3 < x^2\)i.e. \(x^3 - x^2 < 0\)
i.e. \(x^2(x - 1) < 0\)
But \(x^2\) can NOT be negative as being square of a number
i.e. \(x-1 < 0\)
i.e. \(x < 1\)Question: is \(x < 0\) ?Statement 1: \(|x| > x^2\)i.e. \(-1 < x < 1\)
NOT SUFFICIENT
Statement 2: \(x > x^2\)i.e. \(0 < x < 1\)
SUFFICIENT
Answer: Option B
P.S. I don't rate this question appropriate for GMAT practice as the GMAT question do NOT include any redundant information like \(x^3 < x^2\) given in this questionExcuse me, how do you solve the first equation?
\(|x| > x^2\)
Thank you.
jorgetomas9I prefer to avoid mathematically solving such expressions.
There are 4 critical ranges which are
0 to 1
greater than 1
0 to -1 and
Less than -1I always prefer to test the given expression in these ranges to test the validity.
Here I see that \(|x| > x^2\)
so point to be noted is \(|x|\) as well as \(x^2\) will always be positive for all values of x except zero.
also the absolute value of the number should become a smaller number when squared which happened in range
0 to 1i.e. the expression will be valid in ranges
0 to 1 and 0 to -1I HOPE THIS HELPS!!!