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13 Jul 2019, 18:14
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
18% (01:43) correct
82%
(01:42)
wrong
based on 68
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If x = 6m^2 + 4n^2, what is the greatest even number that must be a factor of x?
(1) m and n are even
(2) GCF(m,n)=2
Source: McGraw GMAT 11th Edition
(1) m and n are even
(2) GCF(m,n)=2
Source: McGraw GMAT 11th Edition
RajeshKanjan
Dear GMATPrepNow Brent
Can you please shed light on this question. I do not know how answer would be D.
In Statement 1:
Let m=n=2..........x=24+16=40......then 40 is the greatest even number.
Let m=4 & n=2..........x=96+16=112......then 112 is the greatest even number.
It must insufficient.
In statement 2:
I can repeat same examples above and get same answers ...So insufficient
Answer must be E
What is the problem here? Can you help please?
Thanks in advance
13 Jul 2019, 19:13
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Since,GCF(m,n)=2
m=2k
n=2h where h and k are coprime.
X=6(2k)^2+4(2h)^2
=24k^2+16h^2
=8(3k^2+2h^2)
Since k and h will be odd other term will always be odd.
So 8 will be the greatest even factor of x
Ans. Both statements are required
Posted from my mobile device
m=2k
n=2h where h and k are coprime.
X=6(2k)^2+4(2h)^2
=24k^2+16h^2
=8(3k^2+2h^2)
Since k and h will be odd other term will always be odd.
So 8 will be the greatest even factor of x
Ans. Both statements are required
Posted from my mobile device
