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Bunuel
If x > 8, y > 2x, and z > x, then y + z can equal all of the following EXCEPT

A 56
B 48
C 40
D 32
E 24

x=9
y=19
z=9
y+z= 28
IMO E is exception
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Bunuel
If x > 8, y > 2x, and z > x, then y + z can equal all of the following EXCEPT

A 56
B 48
C 40
D 32
E 24


From stem y > 2x, and z > x
Adding both we get
y + z >3x------(a)

but x>8
So 3x > 24

from (a) y + z >24

Ans E
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Bunuel
If x > 8, y > 2x, and z > x, then y + z can equal all of the following EXCEPT

A 56
B 48
C 40
D 32
E 24

Hi,
Its E.
x is greater than 8
y is greater than 16
z is greater than 8
so, y+z = greater than 16 + greater than 8 = greater than 24.
Hence, y+z cannot be 24, which is Option E.
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Bunuel
If x > 8, y > 2x, and z > x, then y + z can equal all of the following EXCEPT

A 56
B 48
C 40
D 32
E 24


Since x is greater than 8, y is greater than 16, and z is greater than 8. Thus, y + z must be greater than 16 + 8 = 24, so it cannot be 24.

Answer: E
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