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Re: If x = 989 and y = 991, what is the remainder of xy/9? [#permalink]
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lucalimoncelli wrote:
989 -> 990-1
991 -> 990+1

xy -> (990-1)(990+1) -> (990-1)^2
990/9 will leave no remainder, we add 9 to -1 and get 8. Answer A.

Is this a correct application?


Hi,
you have found a good method to answer the Q, but gone wrong in the highlighted portion..
\((990-1)(990+1) = 990^2 - 1^2\)..
now 990 will be div by 9 ..
so our answer is 0-1 = -1..
But remainders are always positive, so -1 will become 9-1 = 8..
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Re: If x = 989 and y = 991, what is the remainder of xy/9? [#permalink]
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Bunuel wrote:
If x = 989 and y = 991, what is the remainder of xy/9?

A. 8
B. 7
C. 6
D. 5
E. 4


Solution:

The remainder when 989 is divided by 9 is 8, and the remainder when 991 is divided by 9 is 1, so the remainder when 989 x 991 is divided by 9 is 8 x 1 = 8.

Answer: A
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Re: If x = 989 and y = 991, what is the remainder of xy/9? [#permalink]
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Re: If x = 989 and y = 991, what is the remainder of xy/9? [#permalink]
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