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If x= (a/2) + (b/2^3) + (c/2^4) , where a,b, and c are each equal to 0 or 1, then x could be each of the following EXCEPT:

a) 1/16
b) 3/16
c) 5/16
d) 10/16
e) 11/16

Fastest way is to get all three fractions together. This is easily done : x = (8a + 2b + c)/16

We can quickly look for the possibilites. 1/16 is possible if a==b=0, c=1; 3/16 is possible if a=0, b=c=1; 5/16 is not possible. 10/16 is possible if a=b=1, c=0, 11/16 is possible if a=b=c=1.

Re: If x= (a/2) + (b/2^3) + (c/2^4) , where a,b, and c are each [#permalink]

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16 Aug 2017, 00:20

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