Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
Join the webinar and learn time-management tactics that will guarantee you answer all questions, in all sections, on time. Save your spot today! Nov. 14th at 7 PM PST
Depending on whether a, b and c take 0 or 1 , we will have 1,3,10 and 11 as sum in the numerator of the expression .
Answer C
_________________
When everything seems to be going against you, remember that the airplane takes off against the wind, not with it. - Henry Ford The Moment You Think About Giving Up, Think Of The Reason Why You Held On So Long +1 Kudos if you find this post helpful
WE: General Management (Pharmaceuticals and Biotech)
Re: If x = a/2 + b/2^3 + c/2^4, where a, b, and c are each equal to 0 or 1
[#permalink]
Show Tags
05 Nov 2015, 23:43
Nice post, tricky one. IMO C A,B,D,E can be easily eliminated as we have 0 or 1 to choose for values of a,b,c respectively. A ->>> easy to get 1/16 (just setting 0 for a & b) B - >>> setting 0 for a, now we have 2/16 (which is 1/8 reversed to 2/16) we get 3/16 D ->>> Getting (1/2 with 8/16 and b=1, c=0) E - >>> a=b=c=1
Re: If x = a/2 + b/2^3 + c/2^4, where a, b, and c are each equal to 0 or 1
[#permalink]
Show Tags
27 Jan 2018, 08:29
Bunuel wrote:
If \(x = \frac{a}{2} + \frac{b}{2^3} + \frac{c}{2^4}\), where a, b, and c are each equal to 0 or 1, then x could be each of the following EXCEPT
(A) 1/16
(B) 3/16
(C) 5/16
(D) 10/16
(E) 11/16
Something that may help you in getting to the answer.. All except D are odd/16, so C/16 =1/16....A now work on other two to see if they add up to answer.. a/2+b/8+1/16.... a=b=1... 1/2+1/8+1/16=11/16 ...E a=0 b=1...1/8+1/16 = 3/16...B a=b=0...1/16...A
Ok now 10/16 is nothing but 5/8.. So c is 0... So 1/2+1/8=5/8...D
close
77% (01:51) correct 
