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jsphcal
If x and y are integers and 3^x-^4 = 3^y+^2, what is y in terms of x?

A x - 6
B x - 5
C x - 2
D x + 2
E x + 6


The question seems confusing

is it 3^(x-4) = 3^(y+2)
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Edited the question.

jsphcal
If x and y are integers and 3^(x-4) = 3^(y+2), what is y in terms of x?

A. x - 6
B. x - 5
C. x - 2
D. x + 2
E. x + 6

\(3^{x-4}=3^{y+2}\) --> \(x-4=y+2\) --> \(y=x-6\).

Answer: A.
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Answer: A

3^(x-4) = 3^(y+2)

Since the base is the same, I isolated the equations and solved for y.

x-4 = y+2
y=x-6
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jsphcal
If x and y are integers and 3^(x-4) = 3^(y+2), what is y in terms of x?

A. x - 6
B. x - 5
C. x - 2
D. x + 2
E. x + 6

Since both bases are the same, we can drop the bases and equate the exponents:

x - 4 = y + 2

x - 6 = y

Answer: A
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jsphcal
If x and y are integers and \(3^{(x-4)} = 3^{(y+2)}\), what is y in terms of x?

A. x - 6
B. x - 5
C. x - 2
D. x + 2
E. x + 6
\(x - 4 = y + 2\)

So \(y = x - 6\), Answer must be (A)
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3^(x-4) = 3^(y+2)

Since the base is the same, we can equate the powers.

x-4 = y+ 2

y = x-6

Option A is the answer.

Thanks,
Clifin J Francis,
GMAT SME
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