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If x and y are non-negative integers such that x + y = 2, then which among the following can be the value of 7x + 3y?

    I. 6
    II. 10
    III. 14

    (A) II only
    (B) I and II
    (C) I and III
    (D) II and III
    (E) I, II and III

The key here is that x and y are non-negative integers
This means there are only 3 possible solutions to the equation x + y = 2

case i: x = 0, y = 2, in which case, 7x + 3y = 7(0) + 3(2) = 6
case ii: x = 1, y = 1, in which case, 7x + 3y = 7(1) + 3(1) =10
case iii: x = 2, y = 0, in which case, 7x + 3y = 7(2) + 3(0) = 14

So, 7x + 3y can equal 6, 10 or 14

Answer: E

Cheers,
Brent

Got it! Thanks! :D
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X and Y can be either 0, 1 or 2 respectively.

If we plug in the different possible values we get

7(1) + 3(1) = 10
7(0) + 3(2) = 6
7(2) + 3(0) = 14

Therefore, I would go with AC E, all results are possible.
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Given x+y=2 and both x and y are positive numbers.
This means that 2 can be the value only if x=y=1.

Now, substitute the value of x and y in 7x+3y which will give the answer as 10.
But that is not provided in the option.

Can you please tell the method of solving it?


It is not positive. It is stated that it is non-negative integer. Which means the options for x and y can be

X + Y = 0,2 or 2,0 or 1,1

Hope it clears the air.

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non -ve integers ; 0,1,2,3,... so on
so for x+y=2
we can have (1,1),(2,0),(0,2)
so 7x+3y can be 6,10,14
IMO E


EgmatQuantExpert
If x and y are non-negative integers such that x + y = 2, then which among the following can be the value of 7x + 3y?

    I. 6
    II. 10
    III. 14

    (A) II only
    (B) I and II
    (C) I and III
    (D) II and III
    (E) I, II and III

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7x+3y= 4x+3x+3y= 4x+3(x+y)=4x+6

x can have 3 values 0.1 and 2

At x=0, 4x+6= 4*0+6=6
At x=1, 4x+6= 4*1+6=10
At x=2, 4x+6= 4*2+6=14

EgmatQuantExpert
If x and y are non-negative integers such that x + y = 2, then which among the following can be the value of 7x + 3y?

    I. 6
    II. 10
    III. 14

    (A) II only
    (B) I and II
    (C) I and III
    (D) II and III
    (E) I, II and III

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Solution


Given:
    • x and y are non-negative integers
    • x + y = 2

To find:
    • The value of 7x + 3y

Approach and Working Out:
    • We are given that x and y are non-negative integers.
      o Implies, x = {0, 1, 2, 3, 4 …….} and y = {0, 1, 2, 3, 4 ………..}

    • And we know that, x + y = 2
    • Thus, the possible values of (x, y), which satisfy the above conditions are (0, 2), (1, 1), (2, 0)

Case 1: (x, y) = (0, 2)
    • Implies, 7x + 3y = 7*0 + 3*2 = 6

Case 2: (x, y) = (1, 1)
    • Implies, 7x + 3y = 7*1 + 3*1 = 10

Case 3: (x, y) = (2, 0)
    • Implies, 7x + 3y = 7*2 + 3*0 = 14

Hence, the correct answer is Option E.

Answer: E


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If x and y are non-negative integers such that x + y = 2, then which among the following can be the value of 7x + 3y?

    I. 6
    II. 10
    III. 14

    (A) II only
    (B) I and II
    (C) I and III
    (D) II and III
    (E) I, II and III

Solution:

Since x and y are non-negative integers, the solutions for the equation x + y = 2 are (x, y) = (0, 2), (1, 1) and (2, 0).

If (x, y) = (0, 2), then 7x + 3y = 7(0) + 3(2) = 6.

If (x, y) = (1, 1), then 7x + 3y = 7(1) + 3(1) = 10.

If (x, y) = (2, 0), then 7x + 3y = 7(2) + 3(0) = 14.

We see that all of them can be the values of 7x + 3y.

Alternate Solution:

Let’s first treat the two equations as a linear system after re-expressing the equation x + y = 2 as 3x + 3y = 6:

For statement I, we have:

7x + 3y = 6
3x + 3y = 6

Subtracting the second equation from the first yields:

4x = 0

x = 0

Thus, statement I can be true (since x is a non-negative integer).

For statement II, we have:

7x + 3y = 10
3x + 3y = 6

Subtracting the second equation from the first yields:

4x = 4

x = 1

Thus, statement II can be true (since x is a non-negative integer).

For statement III, we have:

7x + 3y = 14
3x + 3y = 6

Subtracting the second equation from the first yields:

4x = 8

x = 2

Thus, statement III can be true (since x is a non-negative integer).


Answer: E
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