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If x and y are positive integers and x < y, what is the value of x? [#permalink]
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28 Aug 2017, 04:03
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78% (00:57) correct 22% (01:18) wrong based on 36 sessions
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Re: If x and y are positive integers and x < y, what is the value of x? [#permalink]
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28 Aug 2017, 04:14
Bunuel wrote: If x and y are positive integers and x < y, what is the value of x? (1) The product of x and y is 17. (2) x^2*y = xy (1) 17 = 1* 17 x =1 and y=17 Sufficient (2) x^2 * y = x* y x^2 = x x(x1)=0 x=1 (positive integer) Sufficient D
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Re: If x and y are positive integers and x < y, what is the value of x? [#permalink]
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28 Aug 2017, 04:19
1. X can be 1 or 17 and Y is 17 or 1 respectively. It's not sufficient 2. X can be only 1 therefore Y is 17. It's sufficient.
Answer is B



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Re: If x and y are positive integers and x < y, what is the value of x? [#permalink]
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28 Aug 2017, 04:23
prisukhin wrote: 1. X can be 1 or 17 and Y is 17 or 1 respectively. It's not sufficient 2. X can be only 1 therefore Y is 17. It's sufficient.
Answer is B prisukhinIt is given that x < y in the question . so as per first statement x can only take 1 and y=17..sufficient
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If x and y are positive integers and x < y, what is the value of x? [#permalink]
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Updated on: 28 Aug 2017, 06:51
I didn't notice it. You're right.
Originally posted by prisukhin on 28 Aug 2017, 04:37.
Last edited by prisukhin on 28 Aug 2017, 06:51, edited 1 time in total.



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Re: If x and y are positive integers and x < y, what is the value of x? [#permalink]
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28 Aug 2017, 05:33
S1:xy=17; 17 being prime numbers th eonly factors 1 & 17; so being x<y x=1 >Sufficient
S2:x^2*y=xy; xy=y;x=1; >Sufficient
Ans:D



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Re: If x and y are positive integers and x < y, what is the value of x? [#permalink]
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28 Aug 2017, 20:34
I know I am wrong, I thought the answer was A For the statement 2, here is what I think
x^2 y= xy x^2= x x(x1)=0 x=1 or x =0 or 0 is not a positive integer?
please advise, thank you



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Re: If x and y are positive integers and x < y, what is the value of x? [#permalink]
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28 Aug 2017, 21:35



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Re: If x and y are positive integers and x < y, what is the value of x? [#permalink]
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28 Aug 2017, 21:38
Bunuel wrote: pclawong wrote: I know I am wrong, I thought the answer was A For the statement 2, here is what I think
x^2 y= xy x^2= x x(x1)=0 x=1 or x =0 or 0 is not a positive integer?
please advise, thank you ZERO:1. 0 is an integer. 2.. 0 is an even integer. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even. 3. 0 is neither positive nor negative integer (the only one of this kind).4. 0 is divisible by EVERY integer except 0 itself. Check more here: http://gmatclub.com/forum/numberproper ... 74996.htmlDear Bunuel, so from statement 2, x could be 0 or 1 right? which make statement 2 insuff. ?



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If x and y are positive integers and x < y, what is the value of x? [#permalink]
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28 Aug 2017, 21:41
pclawong wrote: Bunuel wrote: pclawong wrote: I know I am wrong, I thought the answer was A For the statement 2, here is what I think
x^2 y= xy x^2= x x(x1)=0 x=1 or x =0 or 0 is not a positive integer?
please advise, thank you ZERO:1. 0 is an integer. 2.. 0 is an even integer. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even. 3. 0 is neither positive nor negative integer (the only one of this kind).4. 0 is divisible by EVERY integer except 0 itself. Check more here: http://gmatclub.com/forum/numberproper ... 74996.htmlDear Bunuel, so from statement 2, x could be 0 or 1 right? which make statement 2 insuff. ? We are told that x and y are positive integers, so neither of them can be 0 because 0 is NOT a positive integer.
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If x and y are positive integers and x < y, what is the value of x?
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