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If x and y are positive integers and x < y, what is the value of x?

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Math Expert
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If x and y are positive integers and x < y, what is the value of x?  [#permalink]

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28 Aug 2017, 04:03
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68% (00:56) correct 32% (01:27) wrong based on 38 sessions

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If x and y are positive integers and x < y, what is the value of x?

(1) The product of x and y is 17.
(2) x^2*y = xy

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Re: If x and y are positive integers and x < y, what is the value of x?  [#permalink]

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28 Aug 2017, 04:14
1
Bunuel wrote:
If x and y are positive integers and x < y, what is the value of x?

(1) The product of x and y is 17.
(2) x^2*y = xy

(1) 17 = 1* 17
x =1 and y=17
Sufficient

(2) x^2 * y = x* y
x^2 = x
x(x-1)=0
x=1 (positive integer)
Sufficient

D
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Luckisnoexcuse
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Re: If x and y are positive integers and x < y, what is the value of x?  [#permalink]

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28 Aug 2017, 04:19
1. X can be 1 or 17 and Y is 17 or 1 respectively. It's not sufficient
2. X can be only 1 therefore Y is 17. It's sufficient.

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Re: If x and y are positive integers and x < y, what is the value of x?  [#permalink]

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28 Aug 2017, 04:23
prisukhin wrote:
1. X can be 1 or 17 and Y is 17 or 1 respectively. It's not sufficient
2. X can be only 1 therefore Y is 17. It's sufficient.

prisukhin

It is given that x < y in the question .
so as per first statement x can only take 1 and y=17..sufficient
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Luckisnoexcuse
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If x and y are positive integers and x < y, what is the value of x?  [#permalink]

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Updated on: 28 Aug 2017, 06:51
I didn't notice it. You're right.

Originally posted by prisukhin on 28 Aug 2017, 04:37.
Last edited by prisukhin on 28 Aug 2017, 06:51, edited 1 time in total.
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Re: If x and y are positive integers and x < y, what is the value of x?  [#permalink]

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28 Aug 2017, 05:33
S1:xy=17; 17 being prime numbers th eonly factors 1 & 17; so being x<y x=1 -->Sufficient

S2:x^2*y=xy; xy=y;x=1; -->Sufficient

Ans:D
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Re: If x and y are positive integers and x < y, what is the value of x?  [#permalink]

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28 Aug 2017, 20:34
I know I am wrong, I thought the answer was A
For the statement 2, here is what I think

x^2 y= xy
x^2= x
x(x-1)=0
x=1 or x =0
or 0 is not a positive integer?

Math Expert
Joined: 02 Sep 2009
Posts: 55230
Re: If x and y are positive integers and x < y, what is the value of x?  [#permalink]

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28 Aug 2017, 21:35
pclawong wrote:
I know I am wrong, I thought the answer was A
For the statement 2, here is what I think

x^2 y= xy
x^2= x
x(x-1)=0
x=1 or x =0
or 0 is not a positive integer?

ZERO:

1. 0 is an integer.

2.. 0 is an even integer. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even.

3. 0 is neither positive nor negative integer (the only one of this kind).

4. 0 is divisible by EVERY integer except 0 itself.

Check more here: http://gmatclub.com/forum/number-proper ... 74996.html
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Re: If x and y are positive integers and x < y, what is the value of x?  [#permalink]

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28 Aug 2017, 21:38
Bunuel wrote:
pclawong wrote:
I know I am wrong, I thought the answer was A
For the statement 2, here is what I think

x^2 y= xy
x^2= x
x(x-1)=0
x=1 or x =0
or 0 is not a positive integer?

ZERO:

1. 0 is an integer.

2.. 0 is an even integer. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even.

3. 0 is neither positive nor negative integer (the only one of this kind).

4. 0 is divisible by EVERY integer except 0 itself.

Check more here: http://gmatclub.com/forum/number-proper ... 74996.html

Dear Bunuel,
so from statement 2, x could be 0 or 1 right?
which make statement 2 insuff. ?
Math Expert
Joined: 02 Sep 2009
Posts: 55230
If x and y are positive integers and x < y, what is the value of x?  [#permalink]

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28 Aug 2017, 21:41
1
pclawong wrote:
Bunuel wrote:
pclawong wrote:
I know I am wrong, I thought the answer was A
For the statement 2, here is what I think

x^2 y= xy
x^2= x
x(x-1)=0
x=1 or x =0
or 0 is not a positive integer?

ZERO:

1. 0 is an integer.

2.. 0 is an even integer. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even.

3. 0 is neither positive nor negative integer (the only one of this kind).

4. 0 is divisible by EVERY integer except 0 itself.

Check more here: http://gmatclub.com/forum/number-proper ... 74996.html

Dear Bunuel,
so from statement 2, x could be 0 or 1 right?
which make statement 2 insuff. ?

We are told that x and y are positive integers, so neither of them can be 0 because 0 is NOT a positive integer.
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If x and y are positive integers and x < y, what is the value of x?   [#permalink] 28 Aug 2017, 21:41
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