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I know I am wrong, I thought the answer was A For the statement 2, here is what I think

x^2 y= xy x^2= x x(x-1)=0 x=1 or x =0 or 0 is not a positive integer?

please advise, thank you

ZERO:

1. 0 is an integer.

2.. 0 is an even integer. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even.

3. 0 is neither positive nor negative integer (the only one of this kind).

4. 0 is divisible by EVERY integer except 0 itself.

Re: If x and y are positive integers and x < y, what is the value of x? [#permalink]

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28 Aug 2017, 21:38

Bunuel wrote:

pclawong wrote:

I know I am wrong, I thought the answer was A For the statement 2, here is what I think

x^2 y= xy x^2= x x(x-1)=0 x=1 or x =0 or 0 is not a positive integer?

please advise, thank you

ZERO:

1. 0 is an integer.

2.. 0 is an even integer. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even.

3. 0 is neither positive nor negative integer (the only one of this kind).

4. 0 is divisible by EVERY integer except 0 itself.

I know I am wrong, I thought the answer was A For the statement 2, here is what I think

x^2 y= xy x^2= x x(x-1)=0 x=1 or x =0 or 0 is not a positive integer?

please advise, thank you

ZERO:

1. 0 is an integer.

2.. 0 is an even integer. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even.

3. 0 is neither positive nor negative integer (the only one of this kind).

4. 0 is divisible by EVERY integer except 0 itself.