ajit257 wrote:
If x and y are positive integers and \(y=\sqrt{9 - x}\), what is the value of y?
(1) x < 8
(2) y > 1
For the given expression we have x,y are positive integers and therefore squaring both sides
y^2= 9-x
From St 1 we have x< 8 -----> so we have possible value of in the range 0<x<8
Only for x=5, we have y=2
So options B,C and E ruled out
St 2 says y>1 so we have y^2=9-x
Now let us say y=2 so x=5
y=3, we get 9=9-x ----> x=0 which is not possible as "x" is a positive integer
hence y=2
Ans should be D
I messed it with choosing A as ans trying to beat the average time and not carefully solving the st2
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