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gmatbusters
Statement 1: we can have (x, y) as (1, 4) or (4, 9)... so not sufficient
Statement 2: x can be 1, 2, 3 or 4.
Combining statement 1 &2
We can have (x,y) as (1,4) or (4,1)
hence the value of x can be 1 or 4; the unique value of x cannot be determined.
Answer is E

None of x and y can be equal to 1 because if anyone of them is 1 then x, y and xy will not remain DISTINCT
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can x=4 y =16 and xy = 64 be a case as well along with the one mentioned above ?
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yes, you are right... but x can only be 4. hence Answer is C

chirkut1488
can x=4 y =16 and xy = 64 be a case as well along with the one mentioned above ?
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thanks for pointing out my mistake...

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gmatbusters
Statement 1: we can have (x, y) as (1, 4) or (4, 9)... so not sufficient
Statement 2: x can be 1, 2, 3 or 4.
Combining statement 1 &2
We can have (x,y) as (1,4) or (4,1)
hence the value of x can be 1 or 4; the unique value of x cannot be determined.
Answer is E

None of x and y can be equal to 1 because if anyone of them is 1 then x, y and xy will not remain DISTINCT
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If x and y are positive integers, what is the value of x ?

(1) x, y, and xy are distinct perfect squares less than 100.
(2) x < 5

Positive integers are numbers greater than 0 {1,2,3,4,5...}

(1) x, y, and xy are distinct perfect squares less than 100.

x = 4 (2*2), y = 9 (3*3) and xy = 9*4 = 36 (6*6); or,
x = 9 (3*3), y = 49 (7*7) and xy = 9*49 = 196 (14*14).

They are all distinct perfect squares and there is more than one value for x, so insufficient.

(2) x < 5.

So x can be {1,2,3 or 4}, insufficient.

(3) Combining both informations we can only have one value for x < 5 that is a perfect square: \(x=4\), sufficient.

(C) is the answer.
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chirkut1488
can x=4 y =16 and xy = 64 be a case as well along with the one mentioned above ?

Since X<5 then x has to be 4 hence the answer is C
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If x and y are positive integers, what is the value of x?
(1) x, y, and xy are distinct perfect squares less than 100.
(2) x<5

Statement 1: as \(x\), \(y\) & \(xy\) are distinct perfect squares so \(x\) or \(y\) cannot be equal to \(1\) because in that case \(xy\) will be equal to either \(x\) or \(y\).

Some of the possible \(x\) & \(y\) combinations are \((4,9)\) & \((9,4)\). There are multiple values of \(x\). hence Insufficient

Statement 2: \(x\) could be \(1\) or \(4\). Insufficient

Combining 1 & 2: Only possible value for \(x=4\). Sufficient

Option C
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